使用undertow和restasy的HTTP处理器和restasy部署

Question

我正在尝试运行HTTPServer和REST处理程序。一次只有一个人在工作，不能让它同时工作。我需要服务的html页面，也是api。

这是我的代码。

    public class HttpServer {
    private final UndertowJaxrsServer server = new UndertowJaxrsServer();
    private static String rootPath = System.getProperty("user.dir");
    private final Undertow.Builder serverBuilder;
    public HttpServer(Integer port, String host) {
        serverBuilder = Undertow
                .builder()
                .addHttpListener(port, host)
                .setHandler(
                        Handlers.path().addPrefixPath(
                                "/",
                                Handlers.resource(
                                        new FileResourceManager(new File(
                                                rootPath + "/web"), 100))
                                        .addWelcomeFiles(
                                                rootPath + "/web/index.html")));
        server.start(serverBuilder);
    }
    public DeploymentInfo deployApplication(String appPath,
            Class<? extends Application> applicationClass) {
        ResteasyDeployment deployment = new ResteasyDeployment();
        deployment.setApplicationClass(applicationClass.getName());
        return server.undertowDeployment(deployment, appPath);
    }
    public void deploy(DeploymentInfo deploymentInfo) throws ServletException {
        server.deploy(deploymentInfo);
    }
    public static void main(String[] args) throws ServletException {
        HttpServer myServer = new HttpServer(8080, "0.0.0.0");
        DeploymentInfo di = myServer
                .deployApplication("/rest", MyApplication.class)
                .setClassLoader(HttpServer.class.getClassLoader())
                .setContextPath("/my").setDeploymentName("My Application");
        myServer.deploy(di);
    }
}

Answer 1

UndertowJaxrsServer正在重写构建器的文件处理程序:

public UndertowJaxrsServer start(Undertow.Builder builder)
{
    server = builder.setHandler(root).build();
    server.start();
    return this;
}

似乎没有办法将另一个处理程序传递给UndertowJaxrsServer。可能的解决方法是:

• 使用一个资源类部署另一个应用程序，该类只提供文件服务。
• 使用空白的Undertow，轻松轻松地部署JAX-RS。

Answer 2

从3.1.0版本。β 2及以上可以试试

UndertowJaxrsServer server = new UndertowJaxrsServer();
ResteasyDeployment deployment = new ResteasyDeployment();
deployment.setApplicationClass(ExampleApplication.class.getName());
DeploymentInfo deploymentInfo = server.undertowDeployment(deployment, "/");
deploymentInfo.setClassLoader(MyServer.class.getClassLoader());
deploymentInfo.setContextPath("/api");
server.deploy(deploymentInfo);
server.addResourcePrefixPath("/",
        resource(new PathResourceManager(Paths.get(STATIC_PATH),100)).
            addWelcomeFiles("index.html"));
server.start();

RestEasy应用程序将在/api/*和静态文件在/*