在活动组内处理 Tab 键按下以执行后按功能

Question

我正在实现带有 5 个选项卡的选项卡主机。在第 5 个选项卡上，我有一个包含 2 个子活动的活动组。从子活动，如果我按后退按钮，应用程序将返回到父活动。

但是我需要的是按下选项卡按钮，它也必须返回到父活动。

这是我的活动组：

 public class Activitygroup extends ActivityGroup {
private Stack<String> stack;
public static Activitygroup grp;
@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    grp = new Activitygroup();
    if (stack == null) {
        stack = new Stack<String>();
    }
    push("HomeStackActivity", new Intent(this,Extras.class).addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP));
}
@Override
public void finishFromChild(Activity child) {
    pop();
}
@Override
public void onBackPressed() {
    pop();
}
public void push(String id, Intent intent) {
    Window window = getLocalActivityManager().startActivity(id,
            intent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP));
    if (window != null) {
        stack.push(id);
        setContentView(window.getDecorView());
    }
}
public void pop() {
    if (stack.size() == 1) {
        finish();
    }
    LocalActivityManager manager = getLocalActivityManager();
    manager.destroyActivity(stack.pop(), true);
    if (stack.size() > 0) {
        Intent lastIntent = manager.getActivity(stack.peek()).getIntent()
                .addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
        Window newWindow = manager.startActivity(stack.peek(), lastIntent);
        setContentView(newWindow.getDecorView());
    }
}

这是我在 tabhost 活动中处理第二次按 Tab 的位置：

  int numberOfTabs = tabHost.getTabWidget().getChildCount();
    for (int t = 0; t < numberOfTabs; t++) {
        tabHost.getTabWidget().getChildAt(t).setOnTouchListener(new View.OnTouchListener() {
            @Override
            public boolean onTouch(View v, MotionEvent event) {
                if (event.getAction() == MotionEvent.ACTION_UP) {
                    String currentSelectedTag = MainActivity.this.getTabHost().getCurrentTabTag();
                    String currentTag = (String) v.getTag();
                    if (currentSelectedTag.equalsIgnoreCase(currentTag)) {
                        MainActivity.this.getTabHost().setCurrentTabByTag(currentTag);
                        String newSelectedTabTag = MainActivity.this.getTabHost().getCurrentTabTag();
                        if (newSelectedTabTag.toLowerCase().indexOf("extras") != -1) {
     "BACKPRESS FUNCTIONALITY"-MUST BRING THE PARENT ACTIVITY ON TOP HERE
                        } 
                        return true;
                    }
                }
                return false;
            }
        });
    }

默认情况下，苹果手机具有此功能。在按当前活动的选项卡上，它将父活动置于顶部。请建议我一些解决方法。提前谢谢!!

Answer 1

此代码用于从子活动感应 Tab 键按下

int numberOfTabs = tabHost.getTabWidget().getChildCount();
for (int t = 0; t < numberOfTabs; t++) {
    tabHost.getTabWidget().getChildAt(t).setOnTouchListener(new     View.OnTouchListener() {
        @Override
        public boolean onTouch(View v, MotionEvent event) {
            if (event.getAction() == MotionEvent.ACTION_UP) {
                String currentSelectedTag = MainActivity.this.getTabHost().getCurrentTabTag();
                String currentTag = (String) v.getTag();
                if (currentSelectedTag.equalsIgnoreCase(currentTag)) {
                    MainActivity.this.getTabHost().setCurrentTabByTag(currentTag);
                    String newSelectedTabTag = MainActivity.this.getTabHost().getCurrentTabTag();
                    if (newSelectedTabTag.toLowerCase().indexOf("extras") != -1) {
      ****Here call a static method to check whether the child activity is active****
                    childactivity.getappcontext();   
                    } 
                    return true;
                }
            }
            return false;
        }
    });
}

在子活动中粘贴此代码。如果子活动处于活动状态，则在按下选项卡时将关闭它，因此父活动将可见。

 @Override
public void onStart() {
    super.onStart();
    active=true;
}
@Override
public void onStop() {
    super.onStop();
    active=false;
}

public static void getAppContext() {
    if(active){
        System.out.println("gallery");
        galleryActivity1.finish();
    }
}

如果不清楚，请随时询问。很乐意帮忙。