John Resig的Javascript继承片段是否被弃用？

Question

我正在寻找一种简单的方法来创建两个类，一个从另一个继承，子类重新定义父方法之一，并在新方法中调用父方法。

例如，有一个类Animal和Dog，其中Animal类定义了一个方法makeSound()，该方法确定了如何输出声音，然后Dog在其自己的makeSound()方法中重写该方法以发出"呜呜"声，同时也调用Animal的makeSound()来输出该呜呜声。

我在这里查看了John Resig的模型，但它使用了本地arguments.callee属性，该属性在ECMA脚本5中明显贬值。这是否意味着我不应该使用John Resig的代码？

使用Javascript的原型继承模型编写动物/狗代码的一种简洁方法是什么？

Answer 1

这是否意味着我不应该使用John Resig的代码？

正确，在严格模式下使用ES5时不正确。然而，它可以很容易地适应：

/* Simple JavaScript Inheritance for ES 5.1
 * based on http://ejohn.org/blog/simple-javascript-inheritance/
 *  (inspired by base2 and Prototype)
 * MIT Licensed.
 */
(function(global) {
  "use strict";
  var fnTest = /xyz/.test(function(){xyz;}) ? /b_superb/ : /.*/;
  // The base Class implementation (does nothing)
  function BaseClass(){}
  // Create a new Class that inherits from this class
  BaseClass.extend = function(props) {
    var _super = this.prototype;
    // Set up the prototype to inherit from the base class
    // (but without running the init constructor)
    var proto = Object.create(_super);
    // Copy the properties over onto the new prototype
    for (var name in props) {
      // Check if we're overwriting an existing function
      proto[name] = typeof props[name] === "function" && 
        typeof _super[name] == "function" && fnTest.test(props[name])
        ? (function(name, fn){
            return function() {
              var tmp = this._super;
              // Add a new ._super() method that is the same method
              // but on the super-class
              this._super = _super[name];
              // The method only need to be bound temporarily, so we
              // remove it when we're done executing
              var ret = fn.apply(this, arguments);        
              this._super = tmp;
              return ret;
            };
          })(name, props[name])
        : props[name];
    }
    // The new constructor
    var newClass = typeof proto.init === "function"
      ? proto.hasOwnProperty("init")
        ? proto.init // All construction is actually done in the init method
        : function SubClass(){ _super.init.apply(this, arguments); }
      : function EmptyClass(){};
    // Populate our constructed prototype object
    newClass.prototype = proto;
    // Enforce the constructor to be what we expect
    proto.constructor = newClass;
    // And make this class extendable
    newClass.extend = BaseClass.extend;
    return newClass;
  };
  // export
  global.Class = BaseClass;
})(this);

Answer 2

带有Object.create（）的原型链+分配构造函数

function Shape () {
    this.x = 0;
    this.y = 0;
}
Shape.prototype.move = function (x, y) {
    this.x += x;
    this.y += y;
};
function Rectangle () {
    Shape.apply(this, arguments); // super constructor w/ Rectangle configs if any
}
Rectangle.prototype = Object.create(Shape.prototype); // inherit Shape functionality
// works like Rectangle.prototype = new Shape() but WITHOUT invoking the constructor
Rectangle.prototype.constructor = Rectangle;
var rect = new Rectangle();
rect instanceof Rectangle && rect instanceof Shape // returns true

---

从Object.create文档

关于新关键字的信息

Answer 3

这是我为使用链接进行继承以及允许_super工作而提出的。

/**
 * JavaScript simple inheritance
 * by Alejandro Gonzalez Sole (base on John Resig's simple inheritance script)
 * MIT Licensed.
 **/
(function (){
    var initializing = false,
      fnTest = /xyz/.test(function(){xyz;}) ? /b_superb/ : /.* /;
    function Class(){};
    function inheritClass(superClass){
      var self = this;
      function Class(){
        if (!initializing && typeof this._constructor === 'function')
          this._constructor.apply(this, arguments);
      }
      Class.prototype = superClass.prototype;
      Class.prototype._constructor = superClass;
      Class.prototype.constructor = Class;
      Class.extend = extendClass;
      //currenlty if you inhert multiple classes it breaks
      Class.inherit = inheritClass;
      return Class;
    };
    function extendClass(prop) {
      var self = this;
      var _super = self.prototype;
      function Class(){
        if (!initializing && typeof this._constructor === 'function')
          this._constructor.apply(this, arguments);
      }
      initializing = true;
      var prototype = new self();
      initializing = false;
      for (var name in prop) {
        prototype[name] = typeof prop[name] == "function" &&
          typeof _super[name] == "function" && fnTest.test(prop[name]) ?
          (function(name, fn){
            return function() {
              var tmp = this._super;
              this._super = _super[name];
              var ret = fn.apply(this, arguments);
              this._super = tmp;
              return ret;
            };
          })(name, prop[name]) : prop[name];
      }
      Class.prototype = prototype;
      Class.prototype.constructor = Class;
      Class.extend = extendClass;
      Class.inherit = inheritClass;
      return Class;
    };
    Class.extend = extendClass;
    Class.inherit = inheritClass;
})();

//EXAMPLE
function Person(){
  this.name = "No name";
  console.log("PERSON CLASS CONSTRUCTOR")
}
Person.prototype.myMethod = function (t){
  console.log("MY PERSON", t, this.name);
  return -1;
}
var TestPerson = Class.inherit(Person).extend({
    _constructor: function(){
      this._super();
      this.name = "JOhn";
      console.log("TEST PERSON CONSTRUCTOR");
    },
    myMethod: function (t){
      console.log("TEST PERSON", t, this.name);
      return this._super(t)
    }
});

var test = new TestPerson();
console.log(test.myMethod("BA"));

我一直在我的pixi包装上测试它https://github.com/guatedude2/pixijs-cli到目前为止，它对我来说运行得很好。

我在这种方法中遇到的唯一问题是，您只能继承一次。如果再次运行inherit，它将覆盖以前的继承。

Answer 4

我更喜欢TypeScript生成继承形式的方式（从下拉列表中选择简单继承）。那个不使用arguments.callee，而是使用__extends prototype。

var __extends = this.__extends || function (d, b) {
    function __() { this.constructor = d; }
    __.prototype = b.prototype;
    d.prototype = new __();
};
var Animal = (function () {
    function Animal(name) {
        this.name = name;
    }
    Animal.prototype.move = function (meters) {
        alert(this.name + " moved " + meters + "m.");
    };
    return Animal;
})();
var Snake = (function (_super) {
    __extends(Snake, _super);
    function Snake(name) {
        _super.call(this, name);
    }
    Snake.prototype.move = function () {
        alert("Slithering...");
        _super.prototype.move.call(this, 5);
    };
    return Snake;
})(Animal);
var Horse = (function (_super) {
    __extends(Horse, _super);
    function Horse(name) {
        _super.call(this, name);
    }
    Horse.prototype.move = function () {
        alert("Galloping...");
        _super.prototype.move.call(this, 45);
    };
    return Horse;
})(Animal);
var sam = new Snake("Sammy the Python");
var tom = new Horse("Tommy the Palomino");
sam.move();
tom.move(34);