Joining-在PHP中使用键值作为标识符合并多维数组

Question

[{
    "title" = > "CEO",
        "name" = > "George",
        "columns" = > [{
        "display_name" = > "Salary",
        "value" = > "3.85",
    }, {
        "display_name" = > "Bonus",
        "value" = > "994.19",
    }, {
        "display_name" = > "Increment",
        "value" = > "8.15",
    }]
}]

data2 = [{
    "title" = > "CEO",
        "name" = > "George",
        "columns" = > [{
        "display_name" = > "Address",
        "value" = > "Albany",
    }, {
        "display_name" = > "Phone",
        "value" = > "47123",
    }, {
        "display_name" = > "Mobile",
        "value" = > "784123",
    }]
}]

我有上面两个数组，如果两个散列中都满足name = george这样的条件，我想将columns中的值连接到一个数组中。

所需输出如下：

[{
    "title" = > "CEO",
        "name" = > "George",
        "columns" = > [{
        "display_name" = > "Salary",
        "value" = > "3.85",
    }, {
        "display_name" = > "Bonus",    
        "value" = > "994.19",
    }, {
        "display_name" = > "Increment",
        "value" = > "8.15",
    }, {
        "display_name" = > "Address",
        "value" = > "Albany",
    }, {
        "display_name" = > "Phone",
        "value" = > "47123",
    }, {
        "display_name" = > "Mobile",
        "value" = > "784123",
    }]
}]

"name"=>"George"-可能是标识符吗？还是火柴？两者中的id名称相同，然后将列的值转储到联合数组哈希中。

Answer 1

为您制作了一个函数：

<?php
    function array_merge_on_key($original, $new, $key){
        if(is_array($original) && is_array($new)){
            $copy_from = array();
            if(array_key_exists($key, $new)){
                if(is_array($new[$key])){
                    $copy_from = $new[$key];
                }
            }
            return is_null($copy_from) ? array_merge($original[$key], $copy_from) : $original;
        }
        return false;
    }