如何使用Gradle传递参数给main方法

Question

我必须传递两个参数给我的主方法。我的构建脚本是

// Apply the java plugin to add support for Java
apply plugin: 'java'
// In this section you declare where to find the dependencies of your project
repositories {
    // Use 'maven central' for resolving your dependencies.
    mavenCentral()
}
// In this section you declare the dependencies for your production and test code
dependencies {
    compile 'com.example:example-core:1.7.6'
}
task main(type: JavaExec, dependsOn: classes) {
    description = 'This task will start the main class of the example project'
    group = 'Example'
    main = 'com.example.core.Example'
    classpath = sourceSets.main.runtimeClasspath
}

如果我尝试:

gradlew main doc.json text.txt

出现错误。

org.gradle.execution.TaskSelectionException: Task 'doc.json' not found in root project

我怎么能传递参数到我的主方法命令行容易吗?

Answer 1

task run(type: JavaExec) {
    main = "pkg.MainClass"
    classpath = sourceSets.main.runtimeClasspath
    args = ["arg1", "arg2"]
}

Answer 2

您应该使用Gradle命令行文档中列出的use -P。

例如:

gradlew main -Parg1=doc.json --project-prop arg2=text.txt

你可以在Gradle脚本中像这样访问它们:

println "$arg1 $arg2"

Answer 3

task run1(type: JavaExec) {
    main = "pkg.mainclass"
    classpath = sourceSets.main.runtimeClasspath
    args = ["$arg1","$arg2",...]
}
//I have named as run1 it can be any task name
While invoking the gradle script:
c:> gradle run1 -Parg1="test123" -Parg2="sss"