通过数组有条件地迭代

Question

我想把一个数组分解成一个数组。

test_ary = %w(101 This is the first label 102 This is the second label 103 This is
the third label 104 This is the fourth label)
result = iterate_array(test_ary)

预期输出：

#⇒ [
#    "101 This is the first label",
#    "102 This is the second label",
#    "103 This is the third label",
#    "104 This is the fourth label" ]

我写了以下方法：

def iterate_array(ary)
  temp_ary = []
  final_ary =[]
  idx = 0
    temp_ary.push ary[idx]
    idx +=1
    done = ary.length - 1
    while idx <= done
        if ary[idx] =~ /d/
            final_ary.push temp_ary
            temp_ary = []
            temp_ary.push ary[idx]
        else
            temp_ary.push ary[idx]
        end
        idx +=1
    end
    final_ary.push temp_ary
    returned_ary=final_ary.map {|nested_ary| nested_ary.join(" ")}
    returned_ary
end

我认为一定有一种更简单、更优雅的方式。有什么想法吗？

Answer 1

我会使用Enumerable#slice_before:

test_ary.slice_before { |w| w =~ /d/ }.map { |ws| ws.join(" ") }
# => ["101 This is the first label", "102 This is the second label", "103 This is the third label", "104 This is the fourth label"]

编辑：正如@mwp所说，你可以将其缩短：

test_ary.slice_before(/d/).map { |ws| ws.join(" ") }
# => ["101 This is the first label", "102 This is the second label", "103 This is the third label", "104 This is the fourth label"]

Answer 2

▶ test_ary.join(' ').split(/ (?=d)/)
#⇒ [
#  [0] "101 This is the first label",
#  [1] "102 This is the second label",
#  [2] "103 This is the third label",
#  [3] "104 This is the fourth label"
# ]

Answer 3

这将一次遍历数组的两个元素，并在右侧为数字时（或在写入时，当右侧不包含任何非数字字符时）"打断"（切片）它。希望这能有所帮助！

test_ary.slice_when { |_, r| r !~ /D/ }.map { |w| w.join(' ') }

Answer 4

根据函数给我的输出，使用%w(101 This is the first label 102 This is the second label 103 This is the third label 104 This is the fourth label).each { |x| puts x }或使用map，我会得到相同的结果。如果你能发布你期望的输出，那会很有帮助。