是否有可能强制定义已知对象("敌人"one_answers"朋友"),而允许其他对象?
我添加了最后一个对象{"type": "object"}来显示预期的行为——但实际上最后一个对象将推翻两个定义的对象("enemy"one_answers"friend"),导致任何类型的对象在这个模式下都是有效的。如果我删除最后一个对象,它将只允许两个对象,而不允许其他对象。
JSON模式(使用数组进行更快的测试):
{
"type": "array",
"items": {
"anyOf": [
{"$ref": "#/definitions/friend"},
{"$ref": "#/definitions/enemy"},
{"$ref": "#/definitions/future"}
]
},
"definitions": {
"friend": {
"type": "object",
"properties": {
"time": {"type": "string"},
"value": {"type": "number", "minimum": 100}
},
"required": ["time", "value"],
"additionalProperties": false
},
"enemy": {
"type": "object",
"properties": {
"enemy": {"type": "string"},
"color": {"type": "number"}
},
"required": ["enemy", "color"],
"additionalProperties": false
},
"future": {
"type": "object",
"properties": {
"time": {"type": "string"}
}, "required": ["time"],
"additionalProperties": true
}
}
}
示例JSON(前3个应该OK,后3个不应该OK):
[
{"time": "123", "value": 100}, <- should be valid
{"time": "1212", "value": 150}, <- should be valid
{"enemy": "bla", "color": 123}, <- should be valid
{"time": "1212", "value": 50}, <- should be invalid bcoz of "future"
{"enemy": "bla", "color": "123"}, <- shouldn't be valid bcoz of "enemy" schema
{"somethingInFuture": 123, "someFutProp": "ok"} <- should be valid
]
这不是很清楚你真正想要的,但你可能想在这里使用dependencies
和minProperties
的组合。这里使用了该关键字的两种形式:属性依赖和模式依赖。您还希望至少定义一个属性,因此是minProperties
。因此,您可以这样做(注意,我还分解了color
的公共模式;它可能是,也可能不是,你想要的):
{
"type": "object",
"minProperties": 1,
"additionalProperties": {
"type": "string" // All properties not explicitly defined are strings
},
"properties": {
"color": { "type": "number" }
},
"dependencies": {
"enemy": "color", // property dependency
"friend": { // schema dependency
"properties": { "color": { "minimum": 50 } },
"required": [ "color" ]
}
}
}
注意这个模式仍然允许"敌人"one_answers"朋友"同时存在(你原来的模式也是如此)。为了做得更好,应该提供您希望认为有效和无效的json示例。