尝试将两个查询组合到数组中。看看我的代码,首先,我想得到所有的水果都有猫A和val好。第二,我会得到fruit匹配第一个查询的标记,cat c和val要么好要么坏。最后,我想让它们像数组一样$arg=("苹果"=>"4","香蕉"=>"2","耳朵"=>"0");因为梨和val不匹配好或坏,所以0。你有办法做这件事吗?欣赏
<?php
/*
fruit cat val mark
apple A good V
apple c OK 4
banana A good W
banana c bad 2
pear A good W
pear c good 8
*/
$val1 = 'OK';
$val2 = 'bad';
$result1 = $wpdb->get_results( $wpdb->prepare("
SELECT DISTINCT fruit FROM my_table WHERE cat ='A' AND val='%s' ",$val1));
$result2 = $wpdb->get_results( $wpdb->prepare("
SELECT mark FROM my_table WHERE cat ='c' AND val='%s' AND fruit IN (SELECT DISTINCT fruit FROM my_table WHERE cat ='A' AND val='%s')",$val2,$val1));
/*how can I combine these two queries into an array like
$arg = ('apple'=>'4','banana'=>'2','pear'=>'0');
because pear did not match, so 0
*/
?>
最简单的解决方案是重写查询,而不是在php中手动执行,我认为这将达到您想要的效果:
SELECT
t.fruit,
CASE
WHEN t.a_mark IS NOT NULL THEN t.a_mark
WHEN t.c_mark IS NOT NULL THEN t.c_mark
ELSE '0'
END mark
FROM
(SELECT
t.fruit,
( SELECT MAX(mark)
FROM my_table
WHERE fruit = t.fruit AND val = 'good' AND cat = 'A'
AND mark NOT IN ('V', 'W')) a_mark,
( SELECT MAX(mark)
FROM my_table
WHERE fruit = t.fruit AND val in ('OK', 'bad') AND cat = 'c'
AND mark NOT IN ('V', 'W')) c_mark
FROM
(SELECT DISTINCT fruit FROM my_table) t
) t
ORDER BY
t.fruit