如何在Python中获得在线视频文件的视频持续时间?

Question

我有一个视频文件的url列表，我想获得这些视频的时间长度(持续时间)。它们都是mp4格式的。

我似乎能找到的任何支持材料都与本地视频文件有关。这在Python中可能吗?我完全不知道如何解决这个问题

Answer 1

我找到了一个解决方案，如果您在终端运行以下命令，您将获得在线视频的持续时间。

ffprobe -i https://cldup.com/po79gkocrO.mp4 -show_entries format=duration -v quiet -of csv="p=0"

Answer 2

试试我写的这个类:

# coding:utf-8

import struct
import requests

class Mp4info:
    def __init__(self, file):
        self.file = file
        self.seek = 0
        self.duration = 0
        self.s = requests.session()
        self.timeout = 6
        self.s.headers = {
            'Connection': 'keep-alive',
            'Accept': 'text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,image/apng,*/*;q=0.8',
            'Accept-Encoding': 'gzip, deflate',
            'Accept-Language': 'zh-CN,zh;q=0.9,en-US;q=0.8,en;q=0.7',
            'User-Agent': 'Mozilla/5.0 (Macintosh; Intel Mac OS X 10_13_4) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/66.0.3359.139 Safari/537.36'
        }
    # 设置请求头  set request header
    # 传入的seek表示代表需要跳过的字节数量  use seek to skip initial data
    # 在这里进行判断是为了后续获取视频的宽高信息预留的  the condition here is for reserving space for getting the media data
    def _set_headers(self, seek, type):
        if type in ['moov', 'duration']:
            self.s.headers['Range'] = 'bytes={}-{}'.format(seek, seek + 7)
    def _send_request(self):
        try:
            data = self.s.get(url=self.file, stream=True,
                              timeout=self.timeout).raw.read()
        except requests.Timeout:
            raise '连接超时:超过6秒(默认)服务器没有响应任何数据！'  # timeout 6 seconds, the server fails to respond and assumes there is no data
        return data
    def _find_moov_request(self):
        self._set_headers(self.seek, type='moov')
        data = self._send_request()
        size = int(struct.unpack('>I', data[:4])[0])
        flag = data[-4:].decode('ascii')
        return size, flag
    def _find_duration_request(self):
        # 4+4是moov的大小和标识,跳过20个字符，直接读到time_scale，duration  # 4+4 is the first 8 characters denoting charset, skip the next 20 to time_scale and duration
        self._set_headers(seek=self.seek+4+4+20, type='duration')
        data = self._send_request()
        time_scale = int(struct.unpack('>I', data[:4])[0])
        duration = int(struct.unpack('>I', data[-4:])[0])
        return time_scale, duration
    def get_duration(self):
        while True:
            size, flag = self._find_moov_request()
            if flag == 'moov':
                time_scale, duration = self._find_duration_request()
                self.duration = duration/time_scale
                return self.duration
            else:
                self.seek += size

if __name__ == '__main__':
    url = 'http://tekeye.uk/html/images/Joren_Falls_Izu_Japan.mp4'
    file = Mp4info(url)
    a = file.get_duration()
    print(a)

Answer 3

import subprocess
def getLength(filename):
result = subprocess.Popen(["ffprobe", filename],
stdout = subprocess.PIPE, stderr = subprocess.STDOUT)
return [x for x in result.stdout.readlines() if "Duration" in x]

这不是我的代码。我从来没有用过python。我从如何在Python或Django中获得视频持续时间得到了以下答案?