Python SimpleHTTPServer 404 Page

我最近一直在使用Python的SimpleHTTPServer在我的网络上托管文件。我想要一个自定义404页面，所以我研究了这个，并得到了一些答案，但我想仍然使用这个脚本我有。那么，我需要添加什么来获得这个脚本的404页面呢?

import sys
import BaseHTTPServer
from SimpleHTTPServer import SimpleHTTPRequestHandler

HandlerClass = SimpleHTTPRequestHandler
ServerClass  = BaseHTTPServer.HTTPServer
Protocol     = "HTTP/1.0"
if sys.argv[1:]:
    port = int(sys.argv[1])
else:
    port = 80
server_address = ('192.168.1.100', port)
HandlerClass.protocol_version = Protocol
httpd = ServerClass(server_address, HandlerClass)
sa = httpd.socket.getsockname()
print "Being served on", sa[0], "port", sa[1], "..."
httpd.serve_forever()

您实现自己的请求处理程序类并重写send_error方法以仅在代码为404时更改error_message_format:

import os
from BaseHTTPServer import HTTPServer
from SimpleHTTPServer import SimpleHTTPRequestHandler
class MyHandler(SimpleHTTPRequestHandler):
    def send_error(self, code, message=None):
        if code == 404:
            self.error_message_format = "Does not compute!"
        SimpleHTTPRequestHandler.send_error(self, code, message)

if __name__ == '__main__':
    httpd = HTTPServer(('', 8000), MyHandler)
    print("Serving app on port 8000 ...")
    httpd.serve_forever()

默认error_message_format为:

# Default error message template
DEFAULT_ERROR_MESSAGE = """
<head>
<title>Error response</title>
</head>
<body>
<h1>Error response</h1>
<p>Error code %(code)d.
<p>Message: %(message)s.
<p>Error code explanation: %(code)s = %(explain)s.
</body>
"""

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