如果动态多维数组没有值，如何删除该数组键。使用 php

Question

我有两个多维数组，称为$array和$array1，键和值是动态的，我能够找到$array和$array1的array_diff()，我想打印数组键作为表列名和数组值作为表值。我面临的真正问题是，我不能省略没有值的列。这里我给出的样本代码有硬编码的数组键和值。

    <?php
error_reporting(0);
$array[0] = array("key1" => "valueNew", "key2" => "Array2", "key3" => "value3", "key4" => "value4");
$array[1] = array("key1" => "valuetwo", "key2" => "Array2", "key3" => "value3", "key4" => "value4");
$array[2] = array("key1" => "valueThree", "key2" => "Array2", "key3" => "value3", "key4" => "value4");
$array1[0] = array("key1" => "Array1", "key2" => "Array2", "key3" => "Array3", "key4" => "Array4");
$array1[1] = array("key1" => "Array1", "key2" => "Array2", "key3" => "Array3", "key4" => "Array4");
$array1[2] = array("key1" => "Array1", "key2" => "Array2", "key3" => "Array3", "key4" => "Array4");

for($i=0;$i<count($array);$i++){
$implode[$i]=array_diff($array[$i],$array1[$i]);
}
$arrayKeys=array_keys($array[0]);
?>
<table width="200" border="1">
  <tr>
  <?php
  for($i=0;$i<count($arrayKeys);$i++){
  ?>
    <th scope="col"><?php echo $arrayKeys[$i]; ?></th>
    <?php
  }
    ?>
 </tr>
  <tr>
    <?php
  for($i=0;$i<count($arrayKeys);$i++)
  {
    ?>
    <td><?php for($j=0;$j<count($implode);$j++)
    {
        echo $implode[$j][$arrayKeys[$i]]."<br>"; 
    } ?></td>
        <?php
  }
    ?>
  </tr>
</table>

Answer 1

使用array_map和array_filter函数

试试下面的代码代替你的for循环。

$res = array_map(function($a,$b){
  return [array_filter(array_diff($a,$b))];
},$array,$array1);