C# 中的一对多枚举

Question

我有这个 2 枚举，我需要将待处理状态与事务状态相关联

解释一下，对于每笔交易，我使用交易状态枚举只有一个状态，

那么对于每个交易状态，我使用待处理状态枚举有许多待处理的原因？

    /// <summary>
/// Represent all available status for Transaction
/// </summary>
public enum TransactionStatus
{
    New =0,
    Submitted =1,
    PendingStatus = 2,
    Accepted = 3,
    Rejected =4,
    InProgress =5,
    Completed=6,
    Failed=7,
    Canceled=8
}
/// <summary>
/// Represent all available pending status for Transaction
/// </summary>
public enum PendingStatus
{
    PendingA =0,
    PendingX =1,
    PendingY = 2,
}   

我该怎么做？

Answer 1

您可以使用枚举值作为位标志，如此处所述。

通过这种方式，您可以将待处理状态和交易状态混合在一起。

/// <summary>
/// Represent all available status for Transaction
/// </summary>
[Flags]
public enum TransactionStatus
{
    New = 0,
    Submitted = 1,
    PendingStatus = 2,
    Accepted = 4,
    Rejected = 8,
    InProgress = 16,
    Completed = 32,
    Failed = 64,
    Canceled = 128
}
/// <summary>
/// Represent all available pending status for Transaction
/// </summary>
[Flags]
public enum PendingStatus
{
    PendingA = 256,
    PendingX = 512,
    PendingY = 1024
}  
// Example to set transaction as accepted and pending
var MyTransactionStatus = Accepted & PendingA;
// How to check transaction is pendingA regardless of its status ?
if (MyTransactionStatus & PendingA == PendingA) ...

Answer 2

我会使用FlagsAttribute。因此，您可以使用二进制比较。

[FlagsAttribute]
public enum TransactionStatus
{
    New = 0,
    Submitted = 1,
    PendingStatus = 2,
    Accepted = 4,
    // (...)
}
[FlagsAttribute]
public enum PendingStatus
{
    PendingA = 256,
    PendingX = 512,
    PendingY = 1024,
}