PHPSpec缺少匹配器

Question

当我尝试使用诸如shouldBeEqualTo、shouldBeString等PHPSpec匹配器时，我会遇到这个错误，我不知道为什么。

Call to undefined method ProphecyProphecyMethodProphecy::shouldBeEqualTo()

我已经导入了ObjectBehavior，我的规范正在扩展它。我的PHPSpec版本是2.2.1。

<?php
namespace SpecItmoreCoreInteractor;
use ItmoreCoreEntityTask;
use ItmoreCoreEntityTaskDTO;
use ItmoreCoreEntityTaskList;
use ItmoreCoreEntityTaskListDTO;
use ItmoreCoreInteractorAddTask;
use ItmoreCoreRepositoryTaskRepositoryInterface;
use ItmoreCoreRepositoryTasklistRepositoryInterface;
use ItmoreCoreRepositoryUserRepositoryInterface;
use PhpSpecObjectBehavior;
use Prophecy;
class SynchronizeTaskSpec extends ObjectBehavior
{
public function let(
    TaskRepositoryInterface $taskRepository,
    TaskListRepositoryInterface $taskListRepository,
    UserRepositoryInterface $userRepository
) {
    $this->beConstructedWith($taskRepository, $taskListRepository, $userRepository);
}
public function it_is_initializable()
{
    $this->shouldHaveType('ItmoreCoreInteractorSynchronizeTask');
}
public function it_should_throw_exception_when_task_does_not_gave_google_id(
    TaskDTO $taskDTO,
    TaskListDTO $taskListDTO
) {
    $exception = new ErrorException('not a google task');
    $this->shouldThrow($exception)->duringFromGoogleToApp($taskDTO, $taskListDTO);
}
public function it_should_synchronize_existing_task_from_google_to_app(
    TaskDTO $taskDTO,
    TaskListDTO $taskListDTO,
    Task $task,
    TaskRepositoryInterface $taskRepository
) {
    $taskDTO->getGoogleId()->willReturn('taskId');
    $taskRepository->findOneByGoogleId('taskId')->willReturn($task);
    $taskDTO->getTitle()->willReturn('GoogleTitle');
//        $task->getTitle()->shouldBeEqualTo('GoogleTitle');
    $taskDTO->getTitle()->willReturn('exampleTitle');
    $taskRepository->update()->shouldBeCalled();
    $this->fromGoogleToApp($taskDTO, $taskListDTO)->shouldReturnAnInstanceOf('ItmoreCoreEntityTaskDTO');
}
}

Answer 1

您只能在$this->someMethod（）上调用shouldBeEqualTo，对于存根，您需要使用willReturn来存根它们的行为，而不是断言它。

$this是SUS而不是$task。