python 2.7 - httplib.ResponseNotReady with api.ai

Question

我正在尝试用api.ai制作我自己的聊天机器人。

第一次运行正常，但第二次出现错误:

   Traceback (most recent call last):
  File "/root/Documents/Projects/Darlene/core/api.py", line 34, in <module>
    main()
  File "/root/Documents/Projects/Darlene/core/api.py", line 28, in main
    speech, action = b.handle(cmd)
  File "/root/Documents/Projects/Darlene/core/api.py", line 15, in handle
    response = self.request.getresponse().read()
  File "/usr/local/lib/python2.7/dist-packages/apiai/requests/request.py", line 133, in getresponse
    return self._connection.getresponse()
  File "/usr/lib/python2.7/httplib.py", line 1123, in getresponse
    raise ResponseNotReady()
httplib.ResponseNotReady

看起来好像api有问题。但我不确定。下面是我的代码:

import apiai
import json

class Bot(object):
    def __init__(self, client_token='<clientToken>'):
        self.AI = apiai.ApiAI(client_token)
        self.request = self.AI.text_request()
        self.request.lang = 'en'
    def handle(self, text):
        self.request.query = text
        response = self.request.getresponse().read()
        speech = str(json.loads(response)['result']['fulfillment']['speech'])
        action = str(json.loads(response)['result']['action'])
        if action is not '':
            return speech, action
        else:
            return speech, None

def main():
    b = Bot()
    while True:
        cmd = raw_input('me; ')
        speech, action = b.handle(cmd)
        print speech
        if action is not None:
            print 'action'
if __name__ == '__main__':
    main()

有人知道解决这个问题的方法吗?

Answer 1

请不要重复使用请求。仅为每个阶段创建新的请求。同样:

def handle(self, text):
    self.request = self.AI.text_request()
    self.request.lang = 'en'
    self.request.query = text
    response = self.request.getresponse().read()
    speech = str(json.loads(response)['result']['fulfillment']['speech'])
    action = str(json.loads(response)['result']['action'])
    if action is not '':
        return speech, action
    else:
        return speech, None

Answer 2

在read()之后使用decode('utf-8')

既然你刚开始使用Python，那么现在将代码迁移到Python 3.5而不是2.7将是一个好主意…

apiai_request.getresponse () .read () .decode (utf - 8))

请注意，不幸的是，他们在他们的例子中命名为"请求"，因为它与请求库，flask请求等冲突…但这就是生活。