Cython中的AES-NI内在

Question

有没有办法在Cython代码中使用AES-NI指令？

我能找到的最接近的是某人如何访问 SIMD 指令：https://groups.google.com/forum/#!msg/cython-users/nTnyI7A6sMc/a6_GnOOsLuQJ

Python 线程中的 AES-NI 未得到应答：Python 对 AES-NI 的支持

Answer 1

你应该能够定义内联函数，就好像它们是Cython中的普通C函数一样。类似的东西

cdef extern from "emmintrin.h": # I'm going off the microsoft documentation for where the headers are
    # define the datatype as an opaque type
    ctypedef struct __m128i:
        pass
    __m128i _mm_set_epi32 (int i3, int i2, int i1, int i0)
cdef extern from "wmmintrin.h":
    __m128i _mm_aesdec_si128(__m128i v,__m128i rkey)
# then in some Cython function
def f():
   cdef __m128i v = _mm_set_epi32(1,2,3,4)
   cdef __m128i key = _mm_set_epi32(5,6,7,8)
   cdef __m128i result = _mm_aesdec_si128(v,key)

<小时 />

问题"如何将其应用于bytes数组"？首先，您获得字节数组的char*。然后用range迭代它（注意不要跑掉最后）。

# assuming you already have an __m128i key
cdef __m128i v
cdef char* array = python_bytes_array # auto conversion
cdef int i, j
# you NEED to ensure that the byte array has a length divisible by
# 16, otherwise you'll probably get a segmentation fault.
for i in range(0,len(python_bytes_array),16):
    # go over in chunks of 16
    v = _mm_set_epi8(array[i+15],array[i+14],array[i+13],
            # etc... fill in the rest 
            array[i+1], array[i])
    cdef __m128 result = _mm_aesdec_si128(v,key)
    # write back to the same place?
    for j in range(16):
        array[i+j] = _mm_extract_epi8(result,j)