仅在逗号分隔的文件中删除引号之间的逗号

Question

这是我的输入：

"a","b","c","d",",","f"

预期输出：

"a","b","c","d","","f"

基本上，对于每一个出现的","，我都想用""来代替它。此外，我还想为n的行数运行命令，为n的字段数运行命令。

我已经尝试了以下命令

awk-F'"-v OFS="｛对于（i=2；i<=NF；i+=2）gsub（"，"，"，$i）｝1'内卷

但它也删除了双引号，但这不是我所要求的。。。我还需要双引号

Answer 1

你可以试试这个

echo '"a","b","c","d",",","f"'  | sed 's/,",",/,"",/g'

Answer 2

也许这是有效的：

echo '"a","b","c","d",",","f"' | awk '{sub(/42,42,42/,"42,4242")}1'
"a","b","c","d","","f"