如何在PHP中结构化显示多维数组

Question

如何按如下方式显示数组的内容：

 Company Name
  - Username1
  - Username2
 Another Company Name
  - Username3

我创建的阵列如下：

$array[1]['company_id'] = '12';
$array[1]['company_name'] = 'ABC Company';
$array[1]['company_type'] = 'default';
$array[1]['user_id'] = '23';
$array[1]['user_name'] = 'Andrew';
$array[2]['company_id'] = '12';
$array[2]['company_name'] = 'ABC Company';
$array[2]['company_type'] = 'default';
$array[2]['user_id'] = '27';
$array[2]['user_name'] = 'Jeffrey';
$array[3]['company_id'] = '1';
$array[3]['company_name'] = 'Some Company';
$array[3]['company_type'] = 'default';
$array[3]['user_id'] = '29';
$array[3]['user_name'] = 'William';
$array[4]['company_id'] = '51';
$array[4]['company_name'] = 'My Company';
$array[4]['company_type'] = 'default';
$array[4]['user_id'] = '20';
$array[4]['user_name'] = 'Jaime';

Answer 1

这应该做到：

$array[1]['company_id'] = '12';
$array[1]['company_name'] = 'ABC Company';
$array[1]['company_type'] = 'default';
$array[1]['user_id'] = '23';
$array[1]['user_name'] = 'Andrew';
$array[2]['company_id'] = '12';
$array[2]['company_name'] = 'ABC Company';
$array[2]['company_type'] = 'default';
$array[2]['user_id'] = '27';
$array[2]['user_name'] = 'Jeffrey';
$array[3]['company_id'] = '1';
$array[3]['company_name'] = 'Some Company';
$array[3]['company_type'] = 'default';
$array[3]['user_id'] = '29';
$array[3]['user_name'] = 'William';
$array[4]['company_id'] = '51';
$array[4]['company_name'] = 'My Company';
$array[4]['company_type'] = 'default';
$array[4]['user_id'] = '20';
$array[4]['user_name'] = 'Jaime';
foreach( $array as $company ) {
  $companies[$company['company_name']]['users'][] = $company['user_name'];
}

echo '<pre>' . print_r( $companies, true ) . '</pre>';

foreach( $companies as $companyname => $company ) {
   echo $companyname . '<br />';
   foreach( $company['users'] as $user ) {
       echo '  - ' . $user . '<br />';
   }
}

Answer 2

只有一种方法。这将重组数组，使其按公司关联用户，然后只遍历用户。

$companies = array();
foreach($array as $user)
{
    $companies[$user['company_name']][] = $user['user_name'];
}
foreach($companies as $name => $userlist)
{
    echo $name . '<br />';
    foreach($userlist as $user)
    {
        echo ' - ' . $user . '<br />';
    }
}

Answer 3

首先你需要让他们按公司组织：

$companies = array();
foreach($array as $i => $user)
{
  $id = $user['company_id'];
  if(!isset($companies[$id])){
    $companies[$id] = array(
       'company_name' => $user['company_name'],
       'company_type' => $user['company_type'],
       'company_id' => $id,
       'users' => array();
    );
  }
  $companies[$id]['users'][] = array(
     'user_name' => $user['user_name'],
     'user_id' => $user['user_id']
  );
  unset($array[$i]); // just remove the element from the source array... not necessary but possibly useful if its a HUGE list.
}

然后你就可以循环并输出了。

Answer 4

这应该在一次迭代（演示）中使用现有结构：

$currentCompanyId = 0;
foreach ($array as $company) {
    if ($currentCompanyId !== $company['company_id']) {
        printf("%sn", $company['company_name']);
        $currentCompanyId = $company['company_id'];
    }
    printf("t-%sn", $company['user_name']);
}

输出：

ABC Company
    -Andrew
    -Jeffrey
Some Company
    -William
My Company
    -Jaime

该代码段假定数组按公司名称排序（如代码示例所示）。如果不是这样，请先按公司ID进行排序：

usort($array, function($companyA, $companyB) {
    return $companyA['company_id'] - $companyB['company_id'];
});