如何阻止程序生成相同的密钥

Question

我写了一个密码生成器，遇到了这个烦人的问题，它是在同一行重复一个数字或字母。用户为程序提供了一种格式，说明他们希望如何生成密码，例如"C@@d%%%"其中@只有字母，%只有数字，用户还输入数字和字母来生成密码，那么程序应该打印出类似cold123的东西，但它打印出cood111或clld111，我会在下面发布我的代码片段，但请不要说脏话，我对python还很陌生，自学成才，仅仅几个月的python经验。

class G()
    .
    .
    .
    # self.forms is the format the user input they can input things such as C@@d%%% 
    # where @ is only letters and where % is only numbers
    # self.Bank is a list where generated things go 
    AlphaB = [] #list Of All Of The Positions That have The @ sign in The self.forms 
    NumB = [] #list of All of the positions that have a % sign
    for char in self.forms: 
        if char == '@':
            EOL=(self.Position) # Positions End Of Line
            Loc = self.forms[EOL] # Letter
            AlphaB.append(EOL)  

        if char == '%':
            EOL=(self.Position)
            Loc = self.forms[EOL]
            NumB.append(EOL)
        self.Position+=1 # Move right a position
    for pos in AlphaB: 
        for letter in self.alphas: #letters in The User Inputs
            GenPass=(self.forms.replace(self.forms[pos],letter))
            #Not Fully Formatted yet, because Only The letter been formatted
            if GenPass.find('%'):
                for Pos in NumB:
                    for number in self.ints:
                        GenPass=(GenPass.replace(GenPass[Pos],number))
                        if GenPass not in self.Bank:
                            #Cood111
                            print (GenPass)
                            self.Bank.append(GenPass)
            else:
                if GenPass not in self.Bank:
                    print (GenPass)
                    self.Bank.append(GenPass)

Answer 1

GenPass.replace(GenPass[Pos],number)将用number的值替换字符在GenPass[Pos]处每次出现的。您需要确保一次替换一个字符。

Answer 2

创建一个所有字符的列表和一个包含所有数字的列表，然后使用list.pop（randint（0，len（list）-1）选择一个，你总是会像这样选择一个不同的字母/数字，但你也会被限制为10位数字（0-9）和20多个字母。