操作数应包含1列-MySQL NOT IN

Question

SELECT * from campaigns WHERE id not in
(SELECT 
    e.id_campaign, d.name, d.frequency, d.country, d.referral, d.bid, d.status, COUNT(e.id) AS countcap  
    FROM campaigns d
    LEFT JOIN served e
    ON d.id = e.id_campaign 
    WHERE 
        d.status = 'Active'
    GROUP BY e.id_campaign
    HAVING
        countcap < d.frequency)

我得到错误"操作数应包含1列"-但我需要COUNT(e.id(

Answer 1

总是这样：

select *
from campaigns 
where id not in (
    select id_campaign from (
        select e.id_campaign as id_campaign, d.frequency, e.id
        from campaigns d left join served e on d.id = e.id_campaign
        where d.status = 'Active'
        group by e.id_campaign 
        having count(e.id) < d.frequency 
    )
)

Answer 2

"not in"子句需要一个值列表。因此，以下查询将起作用：

SELECT * from campaigns WHERE id not in
(SELECT 
    e.id_campaign
    FROM campaigns d
    LEFT JOIN served e
    ON d.id = e.id_campaign 
    WHERE 
        d.status = 'Active'
    GROUP BY e.id_campaign
    HAVING
        COUNT(e.id) < d.frequency)

如果你能告诉我们表的结构和你想选择什么，我们就能为你找到合适的查询。

Answer 3

SELECT * from campaigns WHERE id not in
(SELECT 
e.id_campaign, d.name, d.frequency, d.country, d.referral, d.bid, d.status, 
COUNT(e.id) AS countcap  
FROM campaigns d....
)

您正在检查不在中的id，因此，您应该只检查一列的检查id。

你可以这样写(它可能无法实现你的目的(：

SELECT * from campaigns WHERE id not in
(SELECT 
e.id_campaign from campaigns d
LEFT JOIN served e
ON d.id = e.id_campaign 
WHERE 
    d.status = 'Active'
GROUP BY e.id_campaign
HAVING
    countcap < d.frequency
)