我想通过搜索输入从数据库中搜索我的数据,一切看起来都很好,但我找不到为什么这个代码不起作用。当我在输入框中输入搜索数据时,任何事情都完成了。请帮助
我的控制器:AdUnitsController
class AdUnitsController extends AppController
{
public function index()
{
$query = $this->_getData();
$this->set('adUnits', $this->paginate($query));
$this->paginate = [
'contain' => ['Networks', 'Games', 'AdTypes']
];
$adUnits = $this->paginate($this->AdUnits);
$this->set(compact('adUnits'));
$this->set('_serialize', ['adUnits']);
}
public function _getData()
{
if (!empty($this->request->data['search'])) {
$search = $this->request->data['search'];
$query = $this->AdUnits->find('All')->where([
'OR' => [
['name LIKE' => '%' . $search . '%'],
],
]);
}
else{
$query = $this->AdUnits->find('All');
}
return $query;
}
我的视图index.ctp:
<label> Search</label>
<?php echo $this->Form->create('AdUnits',array('id' => 'site-search','url'=>array('action'=>'index')));?>
<div>
<?php echo $this->Form->input('search',array('class' => 'form-control', 'label' =>false, 'placeholder' => 'Type Network')); ?>
</div>
<div> <button type="submit"> Search</button>
<?php echo $this->Form->end();?>
搜索不起作用。请帮助
首先简化您的代码:您正在进行两次无理由的分页
public function index()
{
$this->paginate = [
'contain' => ['Networks', 'Games', 'AdTypes']
];
$query = $this->_getData();
$this->set('adUnits', $this->paginate($query));
}
如果您仍然面临问题,那么您的查询可能有错误。我的猜测是name
列是模糊的,所以在您的find()
调用中这样做
['AdUnits.name LIKE' => '%' . $search . '%']
作为附带说明,我建议您阅读文档,特别是学习如何调试代码。
另外,在我看来,_getData
方法应该移动到模型或组件中。
public function index()
{
$query = $this->_getData();
$this->set('adUnits', $this->paginate($query));
$this->paginate = [
'contain' => ['Networks', 'Games', 'AdTypes']
];
$adUnits = $this->paginate($this->AdUnits);
$this->set(compact('adUnits'));
$this->set('_serialize', ['adUnits']);
}
更换为
public function index()
{
$this->paginate = [
'contain' => ['Networks', 'Games', 'AdTypes']
];
$query = $this->_getData();
$this->set('adUnits', $this->paginate($query));
}