我有一个指向intent
的文本文件的Uri
,我正在尝试读取该文件以解析其中的字符串。这是我尝试过的,但FileNotFoundException
失败了。toString()
方法似乎丢失了一个/
java.io.FileNotFoundException:content:/com.google.android.apps.bigtop/attactions/downloads/528c4088144d1515d933ca406b7bc273/attactions/d_0_b562310a_2b6ec1c_c4d5f0d3_73f7489a_711e4cf2/untitled%20text.txt:打开失败:ENOENT(没有这样的文件或目录)
Uri data = getIntent().getData();
String text = data.toString();
if(data != null) {
try {
File f = new File(text);
FileInputStream is = new FileInputStream(f); // Fails on this line
int size = is.available();
byte[] buffer = new byte[size];
is.read(buffer);
is.close();
text = new String(buffer);
Log.d("attachment: ", text);
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
数据的值为:
content://com.google.android.apps.bigtop/attachments/downloads/528c4088144d1515d933ca406b7bc273/attachments/d_0_0_b562310a_52b6ec1c_c4d5f0d3_73f7489a_711e4cf2/untitled%20text.txt
data.getPath()的值为
/attachments/downloads/528c4088144d1515d933ca406b7bc273/attachments/d_0_b562310a_2b6ec1c_c4d5f0d3_73f7489a_11e4cf2/untitled text.txt
我现在正试图直接从Uri而不是路径获取文件:
Uri data = getIntent().getData();
String text = data.toString();
//...
File f = new File(text);
但是f似乎丢失了内容中的一个斜杠://
f:
内容:.com/google.android.apps.bigtop/attachments/downloads/528c4088144d1515d933ca406b7bc273/attachments/d_0_b562310a_2b6ec1c_c4d5f0d3_73f7489a_11e4cf2/untitled%20text.txt
Uri uri = data.getData();
try {
InputStream in = getContentResolver().openInputStream(uri);
BufferedReader r = new BufferedReader(new InputStreamReader(in));
StringBuilder total = new StringBuilder();
for (String line; (line = r.readLine()) != null; ) {
total.append(line).append('n');
}
String content = total.toString();
}catch (Exception e) {
}
从文件读取文本:
private String readText() {
File f = new File(Your_File_Path);
FileInputStream inputStream = null;
try {
inputStream = new FileInputStream(f);
} catch (FileNotFoundException e) {
e.printStackTrace();
}
ByteArrayOutputStream byteArrayOutputStream = new ByteArrayOutputStream();
int i;
try {
i = inputStream.read();
while (i != -1) {
byteArrayOutputStream.write(i);
i = inputStream.read();
}
inputStream.close();
} catch (IOException e) {
e.printStackTrace();
}
return byteArrayOutputStream.toString();
}
此函数将返回String,并根据您的要求使用它。
使用如下:
Log.i("Text from File", readText());
完成