更改左右声道音量分别波出集卷C++

Question

>实际上我想将音频设备的左声道和右声道的音量控制交给用户，该用户为每个声道使用不同的数字。我使用了"waveOutSetVolume（）"。它有 2 个参数，第一个是句柄，第二个是十六进制或 DWORD 编号。

我得到了 2 个数字，每个数字对应每个通道，然后将它们转换为字符串。现在我如何将它们转换为"0x"格式的十六进制？一般来说，如何分别改变每个通道的音量？

void Audio::setChannelsVolume(int rightChannelVolume, int leftChannelVolume)
{
if(leftChannelVolume < 0)
    leftChannelVolume = 0;
if(leftChannelVolume > 100)
    leftChannelVolume = 100;
if(rightChannelVolume < 0)
    rightChannelVolume = 0;
if(rightChannelVolume > 100)
    rightChannelVolume = 100;
stringstream volume;
if(leftChannelVolume < 7 && leftChannelVolume > 0)
    volume << "0x0" << std::hex << soundVolumeCalculus(leftChannelVolume);
else
    volume << "0x"<< std::hex << soundVolumeCalculus(leftChannelVolume);
if(rightChannelVolume < 7 && rightChannelVolume > 0)
    volume << "0" << std::hex << soundVolumeCalculus(rightChannelVolume);
else
    volume << std::hex << soundVolumeCalculus(rightChannelVolume);
string str = volume.str();
cout<<str;
const char* ch = str.c_str();
waveOutSetVolume(hWaveOut,(DWORD)ch);
}

//

/

int Audio::soundVolumeCalculus(int volume)
{
return (int)((65535*volume)/100);
}

Answer 1

我解决了这个问题

DWORD d = 0xffff & soundVolumeCalculus(leftChannelVolume) ;
DWORD dd = 0xffff0000 & (soundVolumeCalculus(rightChannelVolume)*65535);
waveOutSetVolume(hWaveOut,dd+d);