我正在尝试在 C# 中使用 newtonsoft 解析一个相当复杂/不必要的复杂 JSON 输出,但由于某种原因,我的解析器总是返回 null。我已经搜索了SO的各个地方,似乎找不到解决方案。
我尝试解析的 JSON 文件示例:
{
"success": 1,
"d": {
"gameData": {
"MJ2Y7tDg": {
"scores": [
{
"max": 1.83,
"avg": 1.73,
"rest": 2,
"active": true,
"scoreid": "2c556xv464x0x4vtqc"
},
{
"max": 3.47,
"avg": 3.24,
"rest": 2,
"active": true,
"scoreid": "2c556xv498x0x0"
},
{
"max": 6.06,
"avg": 5.08,
"rest": 1,
"active": true,
"scoreid": "2c556xv464x0x4vtqd"
}
],
"count": 62,
"highlight": [
false,
true
]
},
"jZICYUQu": {
"scores": [
{
"max": 2.25,
"avg": 2.13,
"rest": null,
"active": true,
"scoreid": "2c5guxv464x0x4vuiv"
},
{
"max": 3.55,
"avg": 3.29,
"rest": null,
"active": true,
"scoreid": "2c5guxv498x0x0"
},
{
"max": 3.9,
"avg": 3.33,
"rest": null,
"active": true,
"scoreid": "2c5guxv464x0x4vuj0"
}
],
"count": 62,
"highlight": [
false,
false
]
}
}
}
}
这就是我到目前为止所拥有的,我对 JSON 争吵:)非常陌生
public class RootObject
{
public int success { get; set; }
public List<d> d { get; set; }
}
public class d
{
public List<gameData> gameData { get; set; }
}
public class gameData
{
public IDictionary<string, Score> gameData{ get; set; }
public List<scores[]> GameList;
}
public class Score
{
public double max { get; set; }
public double avg { get; set; }
public int rest { get; set; }
public bool active { get; set; }
public string scoreid { get; set; }
}
任何具有更多 JSON 争论经验的人都知道如何让它工作吗?
提前谢谢你。P.S我目前在高中,学习C#
解析器返回 null,因为类的结构与 JSON 的结构不正确。类的正确结构是:
public class RootObject
{
public int success { get; set; }
public Class_d d { get; set; }
}
public class Class_d
{
public Dictionary<string, GameData> gameData { get; set; }
}
public class GameData
{
public List<Score> scores { get; set; }
public int count { get; set; }
public bool[] highlight { get; set; }
}
public class Score
{
public decimal max { get; set; }
public decimal avg { get; set; }
public int? rest { get; set; }
public bool active { get; set; }
public string scoreid { get; set; }
}
您可以按如下方式使用它:
string json = "..."; // the JSON in your example
RootObject root = JsonConvert.DeserializeObject<RootObject>(json);