C语言中ASCII到TBCD的转换



我想将ASCII string转换为TBCD(Telephony Binary-Coded Decimal)格式,反之亦然。我搜索了许多网站,但无法找到我的答案。

最简单的方法可能是使用一对数组将每个ASCII字符映射到对应的TBCD字符。反之亦然

根据我在维基百科上读到的,你应该使用以下内容:

const char *tbcd_to_ascii = "0123456789*#abc";
const char ascii_to_tbcd[] = {
 15, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, /* filler when there is an odd number of digits */
  0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
  0, 0, 0,11, 0, 0, 0, 0, 0, 0,10, 0, 0, 0, 0, 0, /* # * */
  0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 0, 0, 0, 0, 0, 0 /* digits */
  0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
  0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
  0,12,13,14            /* a b c */
};

如果您有TBCD,要将其转换为ASCII,您可以这样做:

/* The TBCD to convert */
int tbcd[] = { 0x10, 0x32, 0x54, 0x76, 0x98, 0xba, 0xdc, 0xfe };
/* The converted ASCII string will be stored here. Make sure to have
   enough room for the result and a terminating 0 */
char ascii[16] = { 0 };
/* Convert the TBCD to ASCII */
int i;
for (i = 0; i < sizeof(tbcd)/sizeof(*tbcd); i++) {
    ascii[2 * i] = tbcd_to_ascii[tbcd[i] & 0x0f];
    ascii[2 * i + 1] = tbcd_to_ascii[(tbcd[i] & 0xf0) >> 4];
}

将ASCII转换为TBCD:

/* ASCII number */
const char *ascii = "0123456789*#abc";
/* The converted TBCD number will be stored here. Make sure to have enough room for the result */
int tbcd[8];
int i;
int len = strlen(ascii);
for (i = 0; i < len; i += 2)
    tbcd[i / 2] = ascii_to_tbcd[ascii[i]]
        | (ascii_to_tbcd[ascii[i + 1]] << 4);
编辑:@Kevin指出TBCD每字节包含两个数字。
#include <ctype.h>
int cnv_tbcd(char *str, char *tbcd) {
  int c = 0;
  int err = 0;
  for (c=0; str[c]; c++) {
    if (isdigit(str[c])) {
      tbcd[c] = str[c] & 0x0f;
    } else {
      switch(str[c]) {
        case '*': tbcd[c]  = 0x0a; break;
        case '#': tbcd[c]  = 0x0b; break;
        case 'a': tbcd[c]  = 0x0c; break;
        case 'b': tbcd[c]  = 0x0d; break;
        case 'c': tbcd[c]  = 0x0e; break;
        default:  tbcd[c] = 0xff; err++;
      }   
    }   
  }
  if (c % 2 == 0) {
    tbcd[c]   = 0x0f;
    tbcd[c+1] = 0;
  }
  return err;
}

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