Ruby引用调用在每个函数中都不起作用

Question

excluded = "a", " an", " the", " at", " in", " on ", "since"     
temp = excluded.split(",").each {|val|  val = val.strip}

但我得到了相同的数组。它不是条纹。我需要在单行中完成此操作

我需要temp中的输出，如["a"、"an"、"the"、"at"、"in"、"on"、"since"]

Answer 1

尝试这个

 temp =  ["a", " an", " the", " at", " in", " on ", "since"].map(&:strip)

Answer 2

正如您从文档中看到的，Array#each返回原始接收器(ary.each {|item| block } → ary(。正如其他人已经指出的那样，您想要的是数组#映射。

此外，由于在数组上调用split，您当前的代码应该引发一个NoMethodError。假设excluded是一个字符串，则以下内容将起作用：

excluded.split(",").map(&:strip) #=> ["a", "an", "the", "at", "in", "on", "since"]

不使用strip，您也可以直接更改拆分内容：

excluded.split(/,s*/) #=> ["a", "an", "the", "at", "in", "on", "since"]

Answer 3

你想要这个吗？：

excluded = ["a", " an", " the", " at", " in", " on ", "since"]
stripped_excluded = excluded.collect{ |i| i.strip }

或快捷方式：

stripped_excluded = excluded.collect(&:strip)

Answer 4

我认为这应该是更简单的方法：

temp = excluded.map(&:strip)
p temp