在将浏览器用户代理与JSON中每个版本的用户代理列表匹配后，检测页面加载上的操作系统和版本

Question

我有一个JSON数组-Level1>>Level2>>Level3。Level1将具有所有操作系统名称，如Windows、Linux等。对于每个操作系统，我们都有级别2阵列，每个类别下都有操作系统和版本。对于ex.windows 10 64位在级别2中，我们有用户代理列表。我们必须将浏览器用户代理与JSON中的userAgent列表相匹配，并显示为检测到的操作系统。我的代码-

    matchTheOSVersionWithUserAgent: function (osVersion){
    var userAgentList = osVersion.userAgent;
    var matchRes;       
    for(i in userAgentList){        
        matchRes = navigator.userAgent.match(userAgentList[i]);             
  }

mock JSON:

osPlatforms: [{
        "name": "Windows",
        "osVersions": [{            
            "name": "Windows 10 (32 bit)",
            "osBit": "32",
            "userAgent": ["Windows 10 (32 bit)", "win10", "Microsoft Windows 10", "Windows NT 10.0",  "Microsoft Windows 10 (64-bit)"],

        }, {                
            "name": "Windows 10 (64 bit)",
             "osBit": "64",
            "userAgent": ["win10", "Microsoft Windows 10", "Windows NT 10.0", "Microsoft Windows 10 (32-bit)"],

        }]

我将matchedRes设置为null，并且没有进行检测。我试着登录mac和windows。有人能帮我吗。TIA。

Answer 1

您需要这样做：

var osPlatforms = [{
  "name": "Windows",
  "osVersions": [{
    "name": "Windows 10 (32 bit)",
    "osBit": "32",
    "userAgent": ["Windows 10 (32 bit)", "win10", "Microsoft Windows 10", "Windows NT 10.0", "Microsoft Windows 10 (64-bit)", "Windows NT 6.1"],
  }, {
    "name": "Windows 10 (64 bit)",
    "osBit": "64",
    "userAgent": ["win10", "Microsoft Windows 10", "Windows NT 10.0", "Microsoft Windows 10 (32-bit)"],
  }]
}];
function matchTheOSVersionWithUserAgent(osVersion) {
  console.log(navigator.userAgent);
  var userAgentList = osVersion.userAgent;
  var matchRes;
  for (var i = 0; i < userAgentList.length; i++) {
    if (navigator.userAgent.match(userAgentList[i])) {
      matchRes = navigator.userAgent.match(userAgentList[i]);
      break;
    }
  }
  console.log(matchRes);
}
matchTheOSVersionWithUserAgent(osPlatforms[0].osVersions[0]);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>

基本上，一旦找到结果，break循环。