我正在编码点火器中做一个项目。我在根据多个条件进行查询时遇到问题。最简单的方法是为每个属性创建单独的条件,但我需要一个优化的方法,因为我稍后将有超过 25 个属性,所以 25 个条件看起来很奇怪。这是示例代码
$this->db->select('*');
$this->db->from('listings');
$this->db->join('hotel_features','listings.id = hotel_features.listing_id');
$this->db->where('listings.country_code',$country_t);
$this->db->like('listings.city',$city_t);
if($room_features_ids != '')
{
$room_features_array[0] = "extra_beds";
$room_features_array[1] = "satellite_tv";
$room_features_array[2] = "airconditioning";
$room_features_array[3] = "cable_tv_service";
$room_features_array[4] = "bathroom";
$room_features_array[5] = "phone";
$room_features_array[6] = "wifi";
$room_features_array[7] = "kitchen";
$room_features_array[8] = "desk";
$room_features_array[9] = "refrigerator";
$room_features_ids = explode("-",$room_features_ids);
// if $room_features_array has 0,1,2 this means first 3 features are available in hotel.
foreach($room_features_ids as $ids)
{
if($room_features_array[$ids] == 'extra_beds')
{
$this->db->where('hotel_features.extra_beds',1);
}
else if($room_features_array[$ids] == 'satellite_tv')
{
$this->db->where('hotel_features.satellite_tv',1);
}
//and so on.... for all properties
}
}
现在我的问题是,有没有优化的方法可以做到这一点?类似的东西
foreach($room_features_ids as $ids)
{
$this->db->where('hotel_features.'.$room_features_array[$ids],1);
}
还是其他方式?提前致谢
有 25 个功能,您还会看到 25 列。如果特征的数量经常变化,为什么不设置一对listing_id
和feature
列呢?这样,只需将存在的要素插入到数据库中。
您的WHERE
查询可以是
foreach($room_features_ids as $ids)
{
$this->db->where('hotel_features.feature', $room_features_array[$ids]);
}
必须存在所有指定的条件。当然,由于您现在正在将hotel_features
中的多行连接到listings
中的单个行,因此您应该聚合来自hotel_features
的行:
$this->db->group_by('listings.id);
$this->db->select('*');
$this->db->from('listings');
$this->db->join('hotel_features','listings.id = hotel_features.listing_id');
$this->db->where('listings.country_code',$country_t);
$this->db->like('listings.city',$city_t);
if($room_features_ids != '')
{
$room_features_array[0] = "extra_beds";
$room_features_array[1] = "satellite_tv";
$room_features_array[2] = "airconditioning";
$room_features_array[3] = "cable_tv_service";
$room_features_array[4] = "bathroom";
$room_features_array[5] = "phone";
$room_features_array[6] = "wifi";
$room_features_array[7] = "kitchen";
$room_features_array[8] = "desk";
$room_features_array[9] = "refrigerator";
$ids = explode("-",$room_features_ids);
$counter = 0;
foreach($room_features_array as $key => $value){
if($value == $room_features_array[$ids[$counter]]){
$this->db->where("hotel_features.$value",1);
}
$counter++;
}
}
使用 $this->db->where_in((; 用于检查多个字段是否包含单个值,反之亦然
在您的情况下,
$condn_arr = array('hotel_features.extra_beds','hotel_features.satellite_tv','hotel_features.airconditioning');
$this->db->where(1,$condn_arr);