关于…选择列,如果发生在同一日期…我收到了这个答案
SELECT a.*
FROM LicenseHistory a
JOIN ( SELECT LicenseID, date as date, COUNT(DISTINCT IPAddress,LicenseID)
FROM LicenseHistory
WHERE (LicenseID= 24965)
GROUP BY LicenseID,Date
/*HAVING COUNT(DISTINCT IPAddress) > 1*/
)b
ON a.LicenseID = b.LicenseID
AND a.date = b.date
order by date desc, LicenseID desc
返回这些结果…
Date UniqueID Users IPAddress Country Count
2013-05-14 24965 15 70.60.96.98 US 1455
2013-05-14 24965 15 72.252.247.148 US 111
2013-03-29 24965 15 184.39.241.223 US 14
计数是严重错误的,因为一个简单的选择,如…
SELECT COUNT(Distinct IPAddress) AS DistinctIPCount
FROM LicenseHistory WHERE (LicenseID=24965)
显示计数为123。我需要这个SQL做的是计算那个ID在那天从那个IPaddress出现的次数。换句话说," 24965在2013-05-14使用IP 70.609.6.98出现了多少次"
如果要统计给定ID,日期和IP的行数,则内部查询中存在错误,所有这些列必须在GROUP BY语句中。试试这个查询:
SELECT *
FROM LicenseHistory a
JOIN ( SELECT LicenseID, date as date, IPAddress, COUNT(*)
FROM LicenseHistory
WHERE (LicenseID= 24965)
GROUP BY LicenseID,Date,IPAddress
)b
ON a.LicenseID = b.LicenseID
AND a.date = b.date
order by date desc, LicenseID desc