如何在同一应用中添加两个不同的ADMOB应用程序ID

Question

你好，这是我用来显示两个不同ADMOB帐户的两个不同ADUNIT ID的代码。但是横幅广告在应用程序中没有看到。

enter code here
private void setUpAds(){
    MobileAds.initialize(this, "ca-app-pub-3940256099942544~3347511713");         
    AdView bannerAdView = new AdView(this);
    int idSelection = random.nextInt(2);
    // Uniform distribution
    if (idSelection == 0) {
        adId = BANNER_ID_1;
    } else {
        adId = BANER_ID_2;
    }
    // Or you can use weighted distribution
    idSelection = random.nextInt(10);
    // %80 chance first, %20 second
    if (idSelection < 8) {
        adId = BANNER_ID_1;
    } else {
        adId = BANER_ID_2;
    }
    bannerAdView.setAdUnitId(adId);
    bannerAdView.setAdSize(AdSize.BANNER);
    AdRequest adRequest6 = new AdRequest.Builder().addTestDevice("E4D1201527AD69E0FD7A0551277A5232").build();
    bannerAdView.loadAd(adRequest6);
}

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_home);

Answer 1

创建两个广告单元，并使用随机选择横幅ID。您也可以使用加权选择，哪个ID更可能被选中。

private static final String BANNER_ID_1 = "ca....";
private static final String BANER_ID_2 = "ca....";
private Random random = new Random();
private String adId = BANNER_ID_1;
private AdView bannerAdView;

private void setUpAds() {
    bannerAdView = new AdView(context);
    int idSelection = random.nextInt(2);
    // Uniform distribution
    if (idSelection == 0) {
        adId = BANNER_ID_1;
    } else {
        adId = BANER_ID_2;
    }
    // Or you can use weighted distribution
    idSelection = random.nextInt(10);
    // %80 chance first, %20 second
    if (idSelection < 8) {
        adId = BANNER_ID_1;
    } else {
        adId = BANER_ID_2;
    }
    bannerAdView.setAdUnitId(adId);
    // Or you can use weighted distribution
    idSelection = random.nextInt(10);
    // %80 chance first, %20 second
    if (idSelection < 8)
    {
        adId = BANNER_ID_1;
    } else {
        adId = BANER_ID_2;
    }
    bannerAdView.setAdUnitId(adId);
}