尝试使用newtonsoft序列化对象到流，获取一个空流

Question

我有一个程序的示例：

using System;
using Newtonsoft.Json;
using System.IO;
public class Program
{
    public static void Main()
    {
        using (var stream = new MemoryStream())
        using (var reader = new StreamReader(stream))
        using (var writer = new StreamWriter(stream))
        using (var jsonWriter = new JsonTextWriter(writer))
        {
            new JsonSerializer().Serialize(jsonWriter, new { name = "Jamie" });
            Console.WriteLine("stream length: " + stream.Length); // stream length: 0
            Console.WriteLine("stream position: " + stream.Position); // stream position: 0
            Console.WriteLine("stream contents: (" + reader.ReadToEnd() + ")"); // stream contents: ()
        }
    }
}

it 应该（根据此页面：https：//www.newtonsoft.com/json/help/html/serializedjson.htm）制作一个包含对象的JSON表示的流：obj但实际上，该流似乎具有长度0，并且是写出时的一个空字符串。我该怎么做才能实现正确的序列化？

以下是运行程序的示例：https：//dotnetfiddle.net/pi1bqe

Answer 1

您需要冲洗jsonserializer，以确保其实际上是写入基础流的数据。该流将处于末端位置，因此您需要将其倒回开始位置以读取数据。

public static void Main()
{
    using (var stream = new MemoryStream())
    using (var reader = new StreamReader(stream))
    using (var writer = new StreamWriter(stream))
    using (var jsonWriter = new JsonTextWriter(writer))
    {
        new JsonSerializer().Serialize(jsonWriter, new { name = "Jamie" });
        jsonWriter.Flush();
        stream.Position = 0;
        Console.WriteLine("stream contents: (" + reader.ReadToEnd() + ")");
    }
}

Answer 2

您需要冲洗作家。

new JsonSerializer().Serialize(jsonWriter, new { name = "Jamie" });
jsonWriter.Flush();