有一个程序的问题，该程序会跳过代码的其他部分

Question

我正在创建一个基于文本的游戏，到目前为止，我已经获得了，如果> else 语句要工作。但是，如果不起作用，则 else。我已经浏览了几个网站和几页，甚至与其他编码员进行了交谈。我已经尽力了，例如用 == 用>"？"。？"）。我有 else 作为嵌套如果>，但也失败了。

public static void FirstRoom(){
    System.out.println("You are in a room filled withndarkness and no memory of yournpast. There are several objectsnscattered on the ground and anlantern in your hand. You findna lighter in your pocket.");
    System.out.println("n ----- n");
    Scanner console = new Scanner(System.in);
    String Call = console.next();
    if (Call.equals("Inspect")) {
        System.out.println("nYou can only see darkness");
        System.out.println("n ----- n");
    } else if(Call.equals("Light Lantern")){
        System.out.println("nYou pull the lighter from your pocket and,nturning the knob, raise thenlantern's wick and light it.");
    System.out.println("n ----- n");
    }else{
        System.out.println("nWhat do you mean?");
        System.out.println("n ----- n");
    FirstRoom();
   }
   String Call2 = console.next();
   if(Call.equals("Inspect")) {
       System.out.println("You see a large sword to yournright and a bag to the left.nThere is a door in frontn of you and a door behind.");
       System.out.println("n ----- n");
   }
}

当我输入 Light Lantern 时，我希望它会说您会从口袋里拉动打火机，然后转动旋钮，抬起灯笼的灯芯并点亮它。取而代之的是，它跳到第二个语句（也应该等待您输入第二个语句），并说您看到右边的一把大剑，左侧有一个袋子。您面前有一扇门，后面有一扇门。

Inspect

你只能看到黑暗

---

灯灯笼你看到一把大剑右，左边有一个袋子。前面有一扇门 你们和后面的一扇门。

---

Answer 1

您需要使用console.nextline（）而不是console.next（）

String Call /*bad name*/ = console.next();

只会采用第一个单词" Light"

String call = console.nextLine(); //using normal JAVA naming conventions

将把所有内容都带到线字符的末端，这意味着您将能够输入多个单词，例如"灯笼"

有关Next（）和NextLine（）之间差异的更多信息，您可以查看此帖子

Answer 2

您在检查Call是否等于"Inspect"之前停止在String Call2 = console.next();处进行输入。您应该检查Call2。

这将是我重新加工该方法的建议：

public static void FirstRoom() {
    System.out.println("You are in a room filled withndarkness and no memory of yournpast. There are several objectsnscattered on the ground and anlantern in your hand. You findna lighter in your pocket.");
    System.out.println("n ----- n");
    Scanner console = new Scanner(System.in);
    String Call;
    boolean exitRoom = false;
    boolean lantern = false;
    while(!exitRoom) {
        Call = console.nextLine();
        if(Call.equals("Inspect") && !lantern) {
            System.out.println("nYou can only see darkness");
            System.out.println("n ----- n");
        } else if(Call.equals("Light Lantern")) {
            System.out.println("nYou pull the lighter from your pocket and,nturning the knob, raise thenlantern's wick and light it.");
            System.out.println("n ----- n");
            lantern = true;
        } else if(Call.equals("Inspect") && lantern) {
            System.out.println("You see a large sword to yournright and a bag to the left.nThere is a door in frontn of you and a door behind.");
            System.out.println("n ----- n");
        } else if(Call.equals("Leave")) {
            System.out.println("You leave the room");
            System.out.println("n ----- n");
            exitRoom = true;
        } else {
            System.out.println("nWhat do you mean?");
            System.out.println("n ----- n");
            FirstRoom();
        }
    }
}

当请求离开房间的命令时，循环结束。