JavaScript 按最近的开始日期时间排序，以呈现到最远的距离和另一个属性

我必须按开始日期时间进行排序，并引用具有多个属性的当前日期时间。例如，我有这个列表：

<ul>
    <li data-startDate="09-04-2019 15:00" data-inplay=false>Name1</li>
    <li data-startDate="09-04-2019 15:30" data-inplay=false>Name2</li>
    <li data-startDate="09-04-2019 15:20" data-inplay=false>Name3</li>
    <li data-startDate="09-04-2019 16:00" data-inplay=false>Name4</li>
    <li data-startDate="09-04-2019 15:00" data-inplay=true> Name5</li>
    <li data-startDate="09-04-2019 15:10" data-inplay=false>Name6</li>
    <li data-startDate="09-04-2019 15:05" data-inplay=true> Name7</li>
    <li data-startDate="08-04-2019 12:05" data-inplay=false>Name8</li>
</ul>

当前日期时间为09-04-2019 15：15，所需的输出应为：

<!--
  Let currentDate = 09-04-2019 15:15
  Sort priority:
    1. inplay is true
    2. startDate is greater than currentDate
    3. startDate is lesser than currentDate
-->
<ul>
  <!-- inplay == true -->
  <li data-startDate="09-04-2019 15:05" data-inplay=true>Name7</li>
  <li data-startDate="09-04-2019 15:00" data-inplay=true>Name5</li>
  <!-- startDate > currentDate -->
  <li data-startDate="09-04-2019 15:20" data-inplay=false>Name3</li>
  <li data-startDate="09-04-2019 15:30" data-inplay=false>Name2</li>
  <li data-startDate="09-04-2019 16:00" data-inplay=false>Name4</li>
  <!-- startDate < currentDate -->
  <li data-startDate="09-04-2019 15:10" data-inplay=false>Name6</li>
  <li data-startDate="09-04-2019 15:00" data-inplay=false>Name1</li>
  <li data-startDate="08-04-2019 12:05" data-inplay=false>Name8</li>
</ul>

我试过这个，但不包括播放参数，而且排序也不太正确

var list = $("ul > li");
var target = new Date().getTime();
var sortByStartTime = function (a, b) {
    var ret = 0;
    var startDateA = $(a).data("startdate");
    var startDateB = $(b).data("startdate");
    var dateA = startDateA.split(" ")[0].split("-");
    var timeA = startDateA.split(" ")[1].split(":");
    var dateB = startDateB.split(" ")[0].split("-");
    var timeB = startDateB.split(" ")[1].split(":");
    startDateA = new Date(dateA[2], dateA[1] - 1, dateA[0], timeA[0], timeA[1]);
    startDateB = new Date(dateB[2], dateB[1] - 1, dateB[0], timeB[0], timeB[1]);
    var dA = Math.abs(startDateA.getTime() - target);
    var dB = Math.abs(startDateB.getTime() - target);
    if (dA < dB) {
        ret = -1;
    } else if (dA > dB) {
        ret = 1;
    }  else {
        ret = 0;
    }
    return ret;
};
list.sort(sortByStartTime);
for (var i = 0; i < list.length; i = i + 1) {
    list[i].parentNode.appendChild(list[i]);
}

基本上，列表应按最近的开始日期时间(相对于当前日期时间(到最远排序

，但如果有一些内涵，它们应该位于列表顶部，按最近的开始日期时间(相对于当前日期时间(到最远排序。我希望我解释得足够清楚。任何帮助不胜感激，谢谢。

您可以使用扩展运算符[...document.querySelectorAll('li')]获取lis元素，例如

数组

然后创建将包含按元素属性data-startDate和布尔属性排序的元素数组的lisSorted data-inplay

法典：

const ul = document.querySelector('ul');
const lis = [...ul.querySelectorAll('li')];
const lisSorted = lis
  .sort((a, b) => {
    const x = a.getAttribute('data-inplay');
    const y = b.getAttribute('data-inplay');
    return ((x === y) ? 0 : x ? -1 : 1) || new Date(b.getAttribute('data-startDate')) - new Date(a.getAttribute('data-startDate'));
  });
ul.append(...lisSorted);

<ul>
  <li data-startDate="09-04-2019 15:00" data-inplay=false>Name1</li>
  <li data-startDate="09-04-2019 15:30" data-inplay=false>Name2</li>
  <li data-startDate="09-04-2019 15:20" data-inplay=false>Name3</li>
  <li data-startDate="09-04-2019 16:00" data-inplay=false>Name4</li>
  <li data-startDate="09-04-2019 15:00" data-inplay=true> Name5</li>
  <li data-startDate="09-04-2019 15:10" data-inplay=false>Name6</li>
  <li data-startDate="09-04-2019 15:05" data-inplay=true> Name7</li>
  <li data-startDate="08-04-2019 12:05" data-inplay=false>Name8</li>
</ul>

排序逻辑：

数据重播真或假排序，使用数字简化排序逻辑(按降序排序(
如果差异相反零的一侧先保持正值，后保持负值(按降序排序(
如果与当前时间相差对于两个日期都在 0 的同一侧，按其绝对值排序值(按升序排序(

var list = Array.from(document.querySelectorAll("ul > li"));
var target = new Date('09-04-2019 15:15');
var boolValue = { true: 1, false: 0 };
var sortByStartTime = function (a, b) {
    var diffA = new Date(a.dataset.startdate) - target;
    var diffB = new Date(b.dataset.startdate) - target;
    var inplayA = boolValue[a.dataset.inplay];
    var inplayB = boolValue[b.dataset.inplay];
    return inplayB - inplayA || (
        diffA < 0 === diffB < 0 ? Math.abs(diffA) - Math.abs(diffB) : diffB - diffA
    );
};
list.sort(sortByStartTime);
for (var i = 0; i < list.length; i = i + 1) {
    list[i].parentNode.appendChild(list[i]);
}

<ul>
  <li data-startDate="09-04-2019 15:00" data-inplay=false>Name1</li>
  <li data-startDate="09-04-2019 15:30" data-inplay=false>Name2</li>
  <li data-startDate="09-04-2019 15:20" data-inplay=false>Name3</li>
  <li data-startDate="09-04-2019 16:00" data-inplay=false>Name4</li>
  <li data-startDate="09-04-2019 15:00" data-inplay=true> Name5</li>
  <li data-startDate="09-04-2019 15:10" data-inplay=false>Name6</li>
  <li data-startDate="09-04-2019 15:05" data-inplay=true> Name7</li>
  <li data-startDate="08-04-2019 12:05" data-inplay=false>Name8</li>
</ul>

PS：将new Date('09-04-2019 15:15');替换为new Date();以获得您想要的。我硬编码日期以显示结果符合您的要求。

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