Python 如何访问类函数变量

Question

这是一个石头剪刀纸游戏代码，这是一个humanplayer与reflectplayer。Reflectplayer上次复制humanplayer移动并显示移动。我试图从play_round访问move2ReflectPlayer。但是怎么做呢？game1.play_round.move2不是工作吗？

import random
moves = ['rock', 'paper', 'scissors']
class Player:
def move(self):
return 'rock'
def learn(self, my_move, their_move):
pass
class RandomPlayer:
def move(self):
all = ["rock","scissors","paper"]
ranint = random.randint(0,2)
return all[ranint]
def learn(self, my_move, their_move):
pass
class HumanPlayer:
def move(self):
ans = input("Rock Paper or Scissors?").lower()
return ans
def learn(self,my_move,their_move):
pass
class ReflectPlayer:
def move(self):
i = 1
RSP = ["rock","paper","scissors"]
print(self.move2)   
if i == 1:
i += 1
return RSP[random.randint(0,2)]
elif game1.play_round.move2 == RSP[0]:
return RSP[0]
elif game1.play_round.move2 == RSP[1]:
return RSP[1]
elif game1.play_round.move2 == RSP[2]:
return RSP[2]
else:
print("Wrong input !")
pass
def learn(self,my_move,their_move):
pass

def beats(one, two):
return ((one == 'rock' and two == 'scissors') or
(one == 'scissors' and two == 'paper') or
(one == 'paper' and two == 'rock'))

class Game:
def __init__(self, p1, p2):
self.p1 = p1
self.p2 = p2
def play_round(self):
move1 = self.p1.move()
move2 = self.p2.move()
print(f"Player 1: {move1}  Player 2: {move2}")
if beats(move1 , move2) == True:
print(f"This Round  : Player 1 WIN")
elif beats(move2 , move1) == True:
print(f"This Round  : Player 2 WIN")
elif move1 == move2:
print("This Round : TIE")    
else:
print("Wrong Input !")
self.p1.learn(move1, move2)
self.p2.learn(move2, move1)
def play_game(self):
print("Game start!")
for round in range(3):
print(f"Round {round}:")
self.play_round()
print("Game over!")
if __name__ == '__main__':
game1 = Game(ReflectPlayer(),HumanPlayer())
game1.play_game()

Answer 1

考虑更改您的实现以将最后播放的动作传递给 move(( 方法。如果您的玩家需要使用以前的动作，那么您可以轻松访问它们。如果不是，就丢弃它们。我假设您将有其他类型的玩家可以从中受益。

rsp = ['rock', 'paper', 'scissors']
class ReflectPlayer:
def move(self, lastOpponentMove):
if lastOpponentMove == None:
return rsp[random.randint(0,2)]
elif lastOpponentMove == rsp[0]:
return rsp[0]
elif lastOpponentMove == rsp[1]:
return rsp[1]
elif lastOpponentMove == rsp[2]:
return rsp[2]
else:
print("Wrong input !")
pass
def learn(self,my_move,their_move):
pass

游戏类的可能改编：

class Game:
def __init__(self, p1, p2):
self.p1 = p1
self.p2 = p2
self.lastP1Move = None
self.lastP2Move = None
def play_round(self):
move1 = self.p1.move(lastP2Move)
move2 = self.p2.move(lastP1Move)
lastP1Move = move1
lastP2Move = move2
print(f"Player 1: {move1}  Player 2: {move2}")
if beats(move1 , move2) == True:
print(f"This Round  : Player 1 WIN")
elif beats(move2 , move1) == True:
print(f"This Round  : Player 2 WIN")
elif move1 == move2:
print("This Round : TIE")    
else:
print("Wrong Input !")
self.p1.learn(move1, move2)
self.p2.learn(move2, move1)

一些注意事项：

• 您在开始时将 rsp 定义为全局列表，以便您可以使用该列表而不是创建新列表。
• 您实施检查以查看它是否是第一场比赛的方式将使我每次都是 1。(我更改了以查看您是否收到无最后一步(。
• 检查play_round方法中的缩进

希望这有帮助