ANTLR4终止Lexer/Parser错误Python

Question

我想知道当lexer或解析器发现不匹配时，如何阻止它运行。例如，如果lexer需要一个"."我希望它不要继续恢复模式。

Answer 1

这就是我的工作原理：

import sys
from antlr4 import *
from bin.LEDSGrammarLexer import LEDSGrammarLexer
from bin.LEDSGrammarParser import LEDSGrammarParser
from bin.LEDSGrammarListener import LEDSGrammarListener
from src.Gramatica import Gramatica
from src.Traductor import Translator
#Add This Library
from antlr4.error.ErrorListener import ErrorListener
import src.CuboSemantico
class MyErrorListener( ErrorListener ):
    def syntaxError(self, recognizer, offendingSymbol, line, column, msg, e):
        print str(line) + ":" + str(column) + ": sintax ERROR, " + str(msg)
        print "Terminating Translation"
        sys.exit()
    def reportAmbiguity(self, recognizer, dfa, startIndex, stopIndex, exact, ambigAlts, configs):
        print "Ambiguity ERROR, " + str(configs)
        sys.exit()
    def reportAttemptingFullContext(self, recognizer, dfa, startIndex, stopIndex, conflictingAlts, configs):
        print "Attempting full context ERROR, " + str(configs)
        sys.exit()
    def reportContextSensitivity(self, recognizer, dfa, startIndex, stopIndex, prediction, configs):
        print "Context ERROR, " + str(configs)
        sys.exit()
def main(argv):
    print "Parsing: " + argv[1] + "n"
    input = FileStream(argv[1])
    lexer = LEDSGrammarLexer(input)
    #This was the key!
    stream = CommonTokenStream(lexer)
    parser = LEDSGrammarParser(stream)
    parser._listeners = [ MyErrorListener() ]
    tree = parser.programa()
    printer = Gramatica()
    walker = ParseTreeWalker()
    result = walker.walk(printer,tree)
    print "Resultado del parseo" + str(result)
    for idx,x in enumerate(printer.Cuadruplos):
        print str(idx) +" - "+str(x)
    translator = Translator()
    translator.translate(printer)
    #print(tree.toStringTree(recog=parser))
if __name__ == '__main__':
    main(sys.argv)

感谢：HAR

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