单词频率计数器Python

Question

与此练习作斗争，此练习必须使用字典并计算每个单词在多个用户输入中出现的次数。它以某种方式工作，但不会将用户输入的每一行中的每个单词原子化。因此，它给了我1 x快乐的日子，而不是将"快乐的日子"的输入计算为1 x快乐和1 x天。我尝试过split（）和lower（），但这会将输入转换为列表，然后我很难将该列表放入字典。

正如你可能已经猜到的，我是一个新手，所以所有的帮助都将不胜感激！

occurrences = {}
while True:
    word = input('Enter line: ')
    word = word.lower() #this is also where I have tried a split()
    if word =='':
        break
occurrences[word]=occurrences.get(word,0)+1
for word in (occurrences):
    print(word, occurrences[word])

编辑

为回应干杯。这最终成为了最终的解决方案。他们并不担心这个案例，希望最终结果排序（）。

occurrences = {}
while True:
    words = input('Enter line: ')
    if words =='':
        break
    for word in words.split(): 
        occurrences[word]=occurrences.get(word,0)+1
for word in sorted(occurrences):
    print(word, occurrences[word])

Answer 1

您所拥有的几乎已经存在，您只想在将单词添加到dict 时循环使用它们

occurrences = {}
while True:
    words = input('Enter line: ')
    words = words.lower() #this is also where I have tried a split()
    if words =='':
        break
    for word in words.split(): 
        occurrences[word]=occurrences.get(word,0)+1
    for word in (occurrences):
        print(word, occurrences[word])

Answer 2

此行不执行：occurrences[word]=occurrence.get（word，0）+1

因为如果它进入if，它就会进入break，并且永远不会执行该行。若不缩进，使其处于外部。

一般来说，发布的代码的缩进是混乱的，我想在实际的代码中并不是这样。

Answer 3

您想要逐行统计数据还是想要整体统计数据？我猜你想要一行接一行，但你也可以通过取消以下代码中的几行来轻松地获得总体统计数据：

# occurrences = dict()  # create a dictionary here if yuo want to have incremental overall stats
while True:
    words = input('Enter line: ')
    if words =='':
        break
    word_list = words.lower().split()
    print word_list
    occurrences = dict()  # create a dict here if you want line by line stats
    for word in word_list:
        occurrences[word] = occurrences.get(word,0)+1
    ## use the lines bellow if you want line by line stats
    for k,v in occurrences.items():
        print k, " X ", v
## use the lines bellow if you want overall stats
# for k,v in occurrences.items():
    # print k, " X ", v