我在网上搜索了所有内容,但没有找到问题的答案。我希望这还没有专门发布,但如果你能指出我在哪里可以找到答案,我将不胜感激。
我能够获取下表数据如下:
id lead_id form_id field_number value
1 1 1 1 Hosker
2 1 1 7 b**********@yahoo.com
3 1 1 6 Hyundai Tournament of Champions
4 1 1 3 Adam Scott
5 1 1 4 Harris English
6 1 1 5 2014-01-02 23:59:47
7 1 1 8 5b409692-e9ed-486e-8d77-7d734f1e023d
并使用此查询字符串获取以下结果:
SELECT id, lead_id, form_id,
MAX(case when field_number = 1 then value end) username,
MAX(case when field_number = 7 then value end) email,
MAX(case when field_number = 6 then value end) tournament_name,
MAX(case when field_number = 3 then value end) primary_golfer,
MAX(case when field_number = 4 then value end) backup_golfer,
MAX(case when field_number = 5 then value end) date,
MAX(case when field_number = 8 then value end) tournament_id
FROM `wp_rg_lead_detail` GROUP BY lead_id
id lead_id form_id field_number value value value value value value value
1 1 1 1 Hosker b**********@yahoo.com Hyundai Tournament of Champions Adam Scott Harris English 2014-01-02 23:59:47 5b409692-e9ed-486e-8d77-7d734f1e023d
我只希望该查询字符串仅在tournament_id列的值等于特定值时才拉取相关数据。我该怎么做?
尝试此查询。我认为您可以使用HAVING
条款。
SELECT id, lead_id, form_id,
MAX(case when field_number = 1 then value end) username,
MAX(case when field_number = 7 then value end) email,
MAX(case when field_number = 6 then value end) tournament_name,
MAX(case when field_number = 3 then value end) primary_golfer,
MAX(case when field_number = 4 then value end) backup_golfer,
MAX(case when field_number = 5 then value end) date,
MAX(case when field_number = 8 then value end) tournament_id
FROM `wp_rg_lead_detail` GROUP BY lead_id
HAVING tournament_id = '5b409692-e9ed-486e-8d77-7d734f1e023d'
sqlFiddle 在 sqlFiddle 中,我有 2 种不同tournament_id的示例数据,并应用 HAVING
子句,以便仅返回该tournament_id的值,您可以尝试删除 HAVING 并看到它返回 2 行。
您的分组依据不是标准的,因为您也选择 id 和form_id。我建议你去掉id或使用MIN(id)或MAX(id)并GROUP BY lead_id,form_id
明白你在问什么,请尝试:
SELECT * FROM TABLE_NAME
WHERE tournament_id = specific_value;