使用boto3上传/传输AWS S3桶

Question

我需要将文件上传到S3，我想知道我应该使用哪个boto3 api调用?

我在boto3文档中找到了两个方法:

• http://boto3.readthedocs.io/en/latest/reference/services/s3.html S3.Client.upload_file
• http://boto3.readthedocs.io/en/latest/reference/customizations/s3.html

是否使用client.upload_file()…

#!/usr/bin/python
import boto3
session = Session(aws_access_key_id, aws_secret_access_key, region)
s3 = session.resource('s3')
s3.Bucket('my_bucket').upload_file('/tmp/hello.txt', 'hello.txt')

或者我使用S3Transfer.upload_file()…

#!/usr/bin/python
import boto3
session = Session(aws_access_key_id, aws_secret_access_key, region)
S3Transfer(session).upload_file('/tmp/hello.txt', 'my_bucket', 'hello.txt')

如有任何建议，不胜感激。提前谢谢。

。．.

可能的解决方案……

# http://boto3.readthedocs.io/en/latest/reference/services/s3.html#examples
# http://boto3.readthedocs.io/en/latest/reference/services/s3.html#S3.Client.put_object
# http://boto3.readthedocs.io/en/latest/reference/services/s3.html#S3.Client.get_object
client = boto3.client("s3", "us-west-1", aws_access_key_id = "xxxxxxxx", aws_secret_access_key = "xxxxxxxxxx")

with open('drop_spot/my_file.txt') as file:
  client.put_object(Bucket='s3uploadertestdeleteme', Key='my_file.txt', Body=file)

response = client.get_object(Bucket='s3uploadertestdeleteme', Key='my_file.txt')
print("Done, response body: {}".format(response['Body'].read()))

Answer 1

最好在客户机上使用该方法。它们是相同的，但是使用客户机方法意味着您不必自己设置东西。

Answer 2

您可以使用Client:低级服务访问:我在https://www.techblog1.com/2020/10/python-3-how-to-communication-with-aws.html