我正在用Java编写一个约会程序,遇到了一个错误,如下所示:
AppointmentNew.java:68: unreported exception java.text.ParseException; must be caught or declared to be thrown
Date lowDate = sdf.parse(stdin.nextLine());
^
AppointmentNew.java:70: unreported exception java.text.ParseException; must be caught or declared to be thrown
Date highDate = sdf.parse(stdin.nextLine());
^
AppointmentNew.java:77: unreported exception java.text.ParseException; must be caught or declared to be thrown
Date newCurrentDate = sdf.parse(currentDate);
该程序假设允许用户进行新的约会,当他们这样做时,他们就可以输入日期和描述(他们可以根据需要多次执行此操作(,之后他们可以选择要打印的程序的日期范围(假设在他们提供的日期范围内打印出约会"。这是我错误发生的地方...
这是我的代码:
import java.util.*;
import java.text.SimpleDateFormat;
import java.util.Date;
public class AppointmentNew
{
public static void main (String[] args)
{
ArrayList<String> list = new ArrayList<String>();
Scanner stdin = new Scanner(System.in);
String choice = "";
int choiceNum = 0;
String date = "";
String descrip = "";
int type = 0;
String typeChose = "";
System.out.println("Welcome to Appointment App!n");
System.out.println("t============================");
do
{
System.out.print("ntMake Choice (1: New, 2: Print Range, 3: Print All, 4: Quit) ");
choice = stdin.nextLine();
choiceNum = Integer.parseInt(choice);
if (choiceNum == 1)
{
System.out.print("nntEnter New Appointment Date in mm/dd/yyyy format: ");
date = stdin.nextLine();
System.out.print("nntEnter New Appointment Description: ");
descrip = stdin.nextLine();
System.out.print("nntEnter Type (1 = Once, 2 = Daily, 3 = Monthly): ");
type = stdin.nextInt();
stdin.nextLine();
if (type == 1)
{
Once once = new Once(date, descrip);
typeChose = "One-Time";
}
else if (type == 2)
{
Daily daily = new Daily(date, descrip);
typeChose = "Daily";
}
else
{
Monthly monthly = new Monthly(date, descrip);
typeChose = "Monthly";
}
String stringToAdd = "";
stringToAdd = (date + " : "" + descrip + "", " + typeChose);
list.add(stringToAdd);
System.out.println("nntNew " + typeChose + " Appointment Added for " + date + "n");
System.out.println("t============================n");
}
if (choiceNum == 2)
{
System.out.print("nntEnter START Date in mm/dd/yyyy format: ");
SimpleDateFormat sdf = new SimpleDateFormat("MM/dd/yyyy");
Date lowDate = sdf.parse(stdin.nextLine());
System.out.print("nntEnter END Date in mm/dd/yyyy format: ");
Date highDate = sdf.parse(stdin.nextLine());
for(int i = 0; i < list.size(); i++)
{
int dateSpot = list.get(i).indexOf(" ");
String currentDate = list.get(i);
currentDate.substring(0, dateSpot);
Date newCurrentDate = sdf.parse(currentDate);
if (newCurrentDate.compareTo(lowDate) >= 0 && newCurrentDate.compareTo(highDate) <= 0)
{
System.out.println("nt" + list.get(i));
}
}
}
if (choiceNum == 3)
{
for(int i = 0; i < list.size(); i++)
{
System.out.println("nt" + list.get(i));
}
}
}while (choiceNum != 4);
}
}
问题是您正在尝试将字符串与日期进行比较。这甚至意味着什么?
您应该将String
转换为Date
(例如,使用 SimpleDateFormat
( - 或者理想情况下,使用 Joda Time - 然后在将它们作为相同类型时比较这些值。
编辑:如评论中所述,这也不是您想要的:
SimpleDateFormat sdf = new SimpleDateFormat("mm/dd/yyyy");
mm
意味着SimpleDateFormat
分钟,而不是几个月。你想要MM/dd/yyyy
。有关更多详细信息,请参阅SimpleDateFormat
文档。
currentDate.compareTo(lowDate)
currentDate
是String
,lowDate
是Date
。你正在尝试compareTo
两件不同的事情。
将currentDate
转换为日期对象,然后调用compareTo();
将 Date 类型的对象与字符串进行比较是正常的。使用SimpleDateFormat(或其他格式(将字符串转换为日期,您将能够比较这两个对象。
Date correctCurrentDate = sdf.parse(currentDate);
为了避免在测试程序中添加try/catch,我通常编写了如下主方法:
public static void main (String[] args) throws Exception
当然,对于在生产环境中运行的程序,您应该在可以处理异常的地方使用 try/catch。但是对于测试程序来说,这很烦人。