Python key sorting

Question

我在python 2上通过谷歌参加了一个在线初学者课程，但我无法找到其中一个问题的答案。给你，提前感谢你的帮助！

# A. match_ends
# Given a list of strings, return the count of the number of
# strings where the string length is 2 or more and the first
# and last chars of the string are the same.
# Note: python does not have a ++ operator, but += works.
def match_ends(words):
  a = []
  for b in words:
retun

我尝试了一些不同的东西。这正是我最后一次尝试的地方，我决定寻求帮助。我花了更多的时间思考这个问题，而不是提及

Answer 1

你应该仔细阅读课程材料。如果你对Python有初级的理解，这个问题可以很容易地解决。请参阅以下代码片段：

def match_ends(words):
  count = 0
  for word in words:
        if len(word) >= 2 and word[0] == word[-1]:
            count += 1
  return count