从服务器中删除浏览器同步.js用于 GULP

Question

我的程序有一个小问题，特别是因为浏览器同步。我想从我的项目中删除浏览器同步。

这是我目前的吞咽/服务器.js

 'use strict';
var path = require('path');
var gulp = require('gulp');
var conf = require('./conf');
var browserSync = require('browser-sync');
var browserSyncSpa = require('browser-sync-spa');
var util = require('util');
var proxyMiddleware = require('http-proxy-middleware');
function browserSyncInit(baseDir, browser)
{
    browser = browser === undefined ? 'default' : browser;
    var routes = null;
    if ( baseDir === conf.paths.src || (util.isArray(baseDir) && baseDir.indexOf(conf.paths.src) !== -1) )
    {
        routes = {
            '/bower_components': 'bower_components'
        };
    }
    var server = {
        baseDir: baseDir,
        routes : routes
    };
    /*
     * You can add a proxy to your backend by uncommenting the line below.
     * You just have to configure a context which will we redirected and the target url.
     * Example: $http.get('/users') requests will be automatically proxified.
     *
     * For more details and option, https://github.com/chimurai/http-proxy-middleware/blob/v0.9.0/README.md
     */
    // server.middleware = proxyMiddleware('/users', {target: 'http://jsonplaceholder.typicode.com', changeOrigin: true});
    browserSync.instance = browserSync.init({
        startPath: '/',
        server   : server,
        ghostMode : false,
        browser  : browser
    });
}
browserSync.use(browserSyncSpa({
    selector: '[ng-app]'// Only needed for angular apps
}));
gulp.task('serve', ['watch'], function ()
{
    browserSyncInit([path.join(conf.paths.tmp, '/serve'), conf.paths.src]);
});
gulp.task('serve:dist', ['build'], function ()
{
    browserSyncInit(conf.paths.dist);
});
gulp.task('serve:e2e', ['inject'], function ()
{
    browserSyncInit([conf.paths.tmp + '/serve', conf.paths.src], []);
});
gulp.task('serve:e2e-dist', ['build'], function ()
{
    browserSyncInit(conf.paths.dist, []);
});

还有我目前的吞咽文件.js

/**
 *  Welcome to your gulpfile!
 *  The gulp tasks are splitted in several files in the gulp directory
 *  because putting all here was really too long
 */
'use strict';
var gulp = require('gulp');
var wrench = require('wrench');
/**
 *  This will load all js or coffee files in the gulp directory
 *  in order to load all gulp tasks
 */
wrench.readdirSyncRecursive('./gulp').filter(function(file) {
  return (/.(js|coffee)$/i).test(file);
}).map(function(file) {
  require('./gulp/' + file);
});

/**
 *  Default task clean temporaries directories and launch the
 *  main optimization build task
 */
gulp.task('default', ['clean'], function () {
  gulp.start('build');
});

我在未安装浏览器同步的服务器上下载这些不同的文件，因此我正在寻找一种方法来启动我的不同gulp.task，而无需通过browserSyncInit或至少有一个不包含对BrowserSync和BrowserSyncSpa的调用的browserSyncInit。

（我指定我的gulp文件夹中还有其他.js，我已经删除了对BrowserSync的调用，并且这些文件没有问题。

Answer 1

删除browser-sync的最简单方法是使用 gulp-connect 。

下面是您的任务服务的示例：

var connect = require('gulp-connect');
gulp.task('serve', ['watch'], function() {
  connect.server({
    root: conf.paths.src,
    port: 3000
  });
}

不要忘记更改端口并安装带有npm install --save gulp-connect的gulp-connect。

这里是吞咽连接包