如何在Java中使用XSLT 2.0和XSLT 3.0

Question

我能够在Java中使用XSLT 1.0，如Folllowing示例所示： -

copy.xml

<?xml version="1.0"?>
<?xml-stylesheet type="text/xsl" href="identityxfm.xsl"?>
<catalog>
    <book id="bk101">
        <author>Gambardella, Matthew</author>
        <title>XML Developer's Guide</title>
        <genre>Computer</genre>
        <price>44.95</price>
        <publish_date>2000-10-01</publish_date>        
        <description>An in-depth look at creating applications with
 XML.</description>
    </book>
    <book id="bk102">
        <author>Ralls, Kim</author>
        <title>Midnight Rain</title>
        <genre>Fantasy</genre>
        <price>5.95</price>
        <publish_date>2000-12-16</publish_date>
        <description>A former architect battles corporate zombies,
 an evil sorceress, and her own childhood to become queen of the
 world.</description>
    </book>
    <book id="bk103">
        <author>Corets, Eva</author>
        <title>Maeve Ascendant</title>
        <genre>Fantasy</genre>
        <price>5.95</price>
        <publish_date>2000-11-17</publish_date>
        <description>After the collapse of a nanotechnology society
 in England, the young survivors lay the foundation for a new 
society.</description>
    </book>
</catalog>

copy.xsl

<?xml version="1.0"?>
<xsl:stylesheet version="1.0"
      xmlns:xsl="http://www.w3.org/1999/XSL/Transform" >
  <xsl:template match="/ | @* | node()">
    <xsl:copy>
      <xsl:apply-templates select="@* | node()"/>
    </xsl:copy>
  </xsl:template>
</xsl:stylesheet>

copy.java

package com.data.transform;
import javax.xml.transform.Transformer;
import javax.xml.transform.TransformerFactory;
import javax.xml.transform.stream.StreamResult;
import javax.xml.transform.stream.StreamSource;
public class Copy {
    public static void main(String args[]) throws Exception {
        StreamSource source = new StreamSource("copy.xml");
        StreamSource stylesource = new StreamSource("copy.xsl");
        TransformerFactory factory = TransformerFactory.newInstance();
        Transformer transformer = factory.newTransformer(stylesource);
        StreamResult result = new StreamResult(System.out);
        transformer.transform(source, result);
      }
}

输出

<?xml version="1.0" encoding="UTF-8"?><?xml-stylesheet type="text/xsl" href="identityxfm.xsl"?><catalog>
    <book id="bk101">
        <author>Gambardella, Matthew</author>
        <title>XML Developer's Guide</title>
        <genre>Computer</genre>
        <price>44.95</price>
        <publish_date>2000-10-01</publish_date>        
        <description>An in-depth look at creating applications with
 XML.</description>
    </book>
    <book id="bk102">
        <author>Ralls, Kim</author>
        <title>Midnight Rain</title>
        <genre>Fantasy</genre>
        <price>5.95</price>
        <publish_date>2000-12-16</publish_date>
        <description>A former architect battles corporate zombies,
 an evil sorceress, and her own childhood to become queen of the
 world.</description>
    </book>
    <book id="bk103">
        <author>Corets, Eva</author>
        <title>Maeve Ascendant</title>
        <genre>Fantasy</genre>
        <price>5.95</price>
        <publish_date>2000-11-17</publish_date>
        <description>After the collapse of a nanotechnology society
 in England, the young survivors lay the foundation for a new 
society.</description>
    </book>
</catalog>

但是，现在我想使用Java中XSLT 2.0和XSLT 3.0（例如xsl:analyze-string，xsl:try等）中包含的几件事。我该怎么做？

Answer 1

获得saxon 9他从maven或sourceforge中获取saxon 9，然后将其放在classpath上，然后在9.8或xslt 3.0支持之前，您在9.8或XSLT 3.0支持之前获得XSLT 2.0支持（流式，高阶，高阶功能除外，xsl:evaluate，模式意识，向后兼容），为9.8。对于完整的XSLT 3.0支持，您需要从Saxonica下载Saxon 9 PE或EE，并将其与您购买的许可证或您在Class Path上要求的试用许可证一起。