希伯来语字符串在preg_match_all中不工作

Question

<?php
$badWords = array("ban","bad","user","pass","stack","name","html");
$string = "Hello my name is user.";
$matches = array();
$matchFound = preg_match_all(
                "/b(" . implode($badWords,"|") . ")b/i", 
                $string, 
                $matches
              );
if ($matchFound) {
  $words = array_unique($matches[0]);
  foreach($words as $word) {
    echo "<li>" . $word . "</li>";
  }
  echo "</ul>";
}
?>

但是当我把$badWords改成希伯来语:

$badWords = array("עזה","חמאס");

并将文本($string)更改为希伯来语:

$string = "חמאס רוצה להרוג אותנו ולא יצליח";

它不工作

为什么?

在英语中工作得很好!

Answer 1

你只需要通知regex引擎你正在使用的模式包含utf-8字符，你必须改变字符类w和单词边界b的含义来处理utf-8字符(因为默认情况下w只包含ascii字母)。要做到这一点，有两种方法:

使用u修饰符

$matchFound = preg_match_all(
            "/b(" . implode($badWords,"|") . ")b/iu", 
            $string, 
            $matches
          );

或将(*UTF8)(*UCP)放在模式的最开头:

$matchFound = preg_match_all(
            "/(*UTF8)(*UCP)b(" . implode($badWords,"|") . ")b/i", 
            $string, 
            $matches
          );

(*UTF8)通知regex引擎模式字符串必须被视为utf8字符串。

(*UCP)将w从默认的[a-zA-Z0-9_]更改为[p{L}p{N}_]