如何在SQL上循环循环，以寻找最接近的最大日期

Question

activity_date   Employee_id
5/29/2017       1
4/15/2017       1
1/14/2017       2
4/14/2017       2
2/15/2017       2
6/15/2017       3
1/13/2017       4

我如何编写一个查询，该查询将在员工的最新活动中拍摄快照，就好像它是5/1/2017一样，然后再次循环并拍摄快照，好像2017年4/1/2017等。<<<<<<<<<<<</p>

这是我想要循环的最后3个日历月的输出。

activity_date   Employee_id  snapshot_date
4/15/2009       1            5/1/2017
4/14/2009       2            5/1/2017
1/13/2009       4            5/1/2017
2/15/2009       2            4/1/2017
1/13/2009       4            4/1/2017
2/15/2009       2            3/1/2017
1/13/2009       4            3/1/2017

谢谢

Answer 1

会有类似的工作吗？

SELECT Max(activity_date), Employee_id,  '2017-05-01' AS snapshotDate
FROM YOUR_TABLE_NAME
WHERE activity_date <= '2017-05-01'
GROUP BY Employee_id

它为您提供这样的结果：

2017-04-15  1   2017-05-01
2017-04-14  2   2017-05-01
2017-01-13  4   2017-05-01

编辑：如果您想要多个循环，则可以使用SQL进行循环。这是代码：

CREATE TABLE prac(
    activity_date DATE,
    Employee_id int
)

INSERT INTO prac (activity_date, Employee_id)
VALUES ('2017-05-29', 1),
('2017-04-15', 1),
('2017-01-14', 2),
('2017-04-14', 2),
('2017-02-15', 2),
('2017-06-15', 3),
('2017-01-13', 4)
 DECLARE @i date = '2017-05-01'
        WHILE @i >= '2017-03-01'
        BEGIN
            SELECT Max(activity_date), Employee_id,  @i AS snapshotDate
            FROM prac
            WHERE activity_date <= @i
            GROUP BY Employee_id
            SET @i = DATEADD(MONTH,-1,@i)
        END

上面的代码将循环到3月至5月，输出看起来像这样：

2017-04-15  1   2017-05-01
2017-04-14  2   2017-05-01
2017-01-13  4   2017-05-01
2017-02-15  2   2017-04-01
2017-01-13  4   2017-04-01
2017-02-15  2   2017-03-01
2017-01-13  4   2017-03-01

Answer 2

一种方法是 UNION ...

select
   employee_id,
   Max(activity_date) activity_date,
   '2017-05-01' as snap_shot
from SomeTable 
where activity_date <= '20170501'
group by employee_id 
union
select
   employee_id,
   Max(activity_date) activity_date,
   '2017-04-01' as snap_shot
from SomeTable 
where activity_date <= '20170401'
group by employee_id 
union
select
   employee_id,
   Max(activity_date) activity_date,
   '2017-03-01' as snap_shot
from SomeTable 
where activity_date <= '20170301'
group by employee_id 

，或者如果您希望有一堆日期，请使用CTE ...只需设置@start和@end变量

declare @table table (activity_date date, Employee_id int)
insert into @table
values
('5/29/2017',1),
('4/15/2017',1),
('1/14/2017',2),
('4/14/2017',2),
('2/15/2017',2),
('6/15/2017',3),
('1/13/2017',4)

DECLARE @start DATE, @end DATE;
SELECT @start = '20170301', @end = '20170501'
;WITH n AS 
(
  SELECT TOP (DATEDIFF(month, @start, @end) + 1) 
  n = ROW_NUMBER() OVER (ORDER BY [object_id])
  FROM sys.all_objects
),
x as
(
    SELECT DATEADD(month, n-1, @start)  DT
    FROM n
)

select
    Employee_id
    ,Max(activity_date) activity_date
    ,DT
from @table
inner join x on activity_date <= DT
group by Employee_id, DT
order by DT desc