我第一次打开按钮后，LED 一直亮着

Question

>我试图通过将变量 e 设置为 1 或 0 来将按钮转换为开关，具体取决于引脚 12 是返回高还是低，但是按下按钮一次后，LED 打开并且无论我再次按下按钮多少次都不会关闭。

#define boton 12
#define gled 7
#define rled 4
#define yled 8
int e=0;
int botonst=LOW;
void setup() {
// put your setup code here, to run once:
pinMode(boton,INPUT);
pinMode(gled,OUTPUT);
pinMode(rled,OUTPUT);
pinMode(yled,OUTPUT);

}
void loop() {
// put your main code here, to run repeatedly:
botonst=digitalRead(boton);
if ((botonst==HIGH) && (e=1)){

digitalWrite(yled,HIGH);
e=0;

}

else{
if(e=0){
digitalWrite(yled,LOW);
e=1;
}
}


delay(50);



}
```C

Answer 1

你的逻辑不清楚！ 但我想你有按钮和 LED，并且每次单击按钮时都尝试切换 LED，如果这是您尝试做的事情..然后使用此代码

#define boton 12   // button conect on pin 12
#define yled 8     // led conect on pin 8
bool ledMode = false;   // this  mode use to save the current led state ( high or low ) 
int botonst=LOW;     

void setup() {
pinMode(boton,INPUT); // make button as input pin
pinMode(yled,OUTPUT); // make led as output pin
}
void loop() {
botonst=digitalRead(boton); // read the button state
if (botonst==HIGH){            // if button is clicked  (assume you connect the button as active high)
ledMode ^= true;             // toggle the mode (if it true make it false and if it false make it ture)
if(ledMode == false)         //if led mod is off
digitalWrite(yled,HIGH);   // turn led on
else                        // if led mode is on
digitalWrite(yled,LOW);     // turn led off
}
delay(200);   //delay for Depounceing (if you use hardware Depounce technique remove it)
}