如何获得两小时间隔的日期时间

Question

我尝试了几种方法，但没有找到可行的解决方案
从今天到接下来的五天，我需要两个小时的datetime间隔，时间范围必须是早上7:00到晚上22:00。

到目前为止，我尝试的是：

let cal = Calendar(identifier: Calendar.Identifier.gregorian)
for i in 1..<6{
let date = Date()
var components = DateComponents()
components.setValue(i, for: .day)
let expirationCal = cal.date(byAdding: components, to: date)

let calendar = NSCalendar.autoupdatingCurrent
for i  in 0..<12 {
var  newDateTime = calendar.date(byAdding: Calendar.Component.hour, value: 1, to: expirationCal!)
let currentHour = calendar.component(.hour, from: newDateTime!)
let hourInt = Int(currentHour.description)!
if hourInt >= 8 && hourInt <= 22 {
print(newDateTime)
}
}
}

Answer 1

我的建议：

• 计算开始和结束日期

• 从开始到结束按整小时枚举日期，并过滤给定范围中的偶数日期

  let cal = Calendar(identifier: .gregorian)
  let startDate = Date()
  let endDate = cal.date(byAdding: .day, value: 5, to: startDate)
  let fullHourComponents = DateComponents(minute: 0, second: 0)
  var dates = [Date]()
  cal.enumerateDates(startingAfter: startDate, matching: fullHourComponents, matchingPolicy: .nextTime) { date, strict, stop in
  if let validDate = date {
  if validDate == endDate { stop = true; return}
  let currentHour = cal.component(.hour, from: validDate)
  if currentHour.isMultiple(of: 2), (7..<23) ~= currentHour {
  dates.append(validDate)
  }
  }
  }
  print(dates)
  

考虑打印日期为UTC