Round不接受参数类型(Int)

Question

我想创建一个关于除法的数学测试的应用程序。我知道我不能创造无限重复的小数，我必须保持这些数字是随机的。因此，在我从arc4random_uniform中生成数字后，我试图使用round函数。但是上面写着

找不到接受参数类型(Int)的重载for round

如何解决这个问题?

下面是我的代码:

 var randomNumber:UInt32 = arc4random_uniform(999)
 var randomNumber2:UInt32 = arc4random_uniform(999)
 // 1000 is my maximum number for now.
 randomNumber += 1
 randomNumber2 += 1
 if operation.text == "/" {
     if randomNumber < randomNumber2 {
         var between:UInt32 = 1000 - randomNumber2
         randomNumber = randomNumber2 + arc4random_uniform(between - 1)
         // making sure that randomNumber is not smaller than randomNumber2,
         // therefore all results are positive.
     }
     var answer:Int = round(Int(randomNumber)/Int(randomNumber2))
 }

Answer 1

您必须将Float值传递给round，因为它没有使用Int值的原型:

var answer = round(Float(randomNumber)/Float(randomNumber2))