我想使用 StringTokenizer 搜索字符串，但我正在寻找的字符串中有一个分隔符 - Java

Question

我有一个名为quotes.txt的外部文件，我将向您展示该文件的一些内容：

1 Everybody's always telling me one thing and out the other.
2 I love criticism just so long as it's unqualified praise.
3 The difference between 'involvement' and 'commitment' is like an eggs-and-ham 
  breakfast: the chicken was 'involved' - the pig was 'committed'.

我使用了这个：StringTokenizer str = new StringTokenizer(line, " .'");

这是搜索的代码：

String line = "";
boolean wordFound = false;
while((line = bufRead.readLine()) != null) {
    while(str.hasMoreTokens()) {
       String next = str.nextToken();
       if(next.equalsIgnoreCase(targetWord) {
            wordFound = true;
            output = line;
            break;
       }
    }
    if(wordFound) break;
    else output = "Quote not found";
}

现在，我想在第1行和第2行搜索字符串"Everybody's"和"it's"，但它不起作用，因为撇号是分隔符之一。如果删除该分隔符，则无法在第3行中搜索"involvement"、"commitment"、"involved"和"committed"。

我可以用什么合适的代码来处理这个问题？请帮忙，谢谢。

Answer 1

我建议使用正则表达式（Pattern类）而不是StringTokenizer。例如：

final Pattern targetWordPattern =
    Pattern.compile("\b" + Pattern.quote(targetWord) + "\b",
                    Pattern.CASE_INSENSITIVE);
String line = "";
boolean wordFound = false;
while((line = bufRead.readLine()) != null) {
    if(targetWordPattern.matcher(line).find()) {
        wordFound = true;
        break;
    }
    else
        output = "Quote not found";
}

Answer 2

用空格标记，然后用'字符修剪。