如何使用php将sql查询的结果输入到html表中

我正在寻找一种解决方案，即它通过我的数据库查询中的每条记录循环，并在一个具有固定表标题的html表中给出它自己的行。下面是我用来查询数据和获取结果的当前php。我的表的每个标题名称是:PropertyType、Description、RentPrice和Location。然而，由于某些原因，当我试图运行我的代码时，屏幕上没有显示

<!DOCTYPE html>
<html lang="en">
<body>
<p style ="text-align: center" id="php_style">
<?php
    error_reporting(E_ERROR | E_PARSE);
    session_start();
    $counter_name = "counter.txt";
    // Check if a text file exists. If not create one and initialize it to zero.
    if (!file_exists($counter_name)) {
      $f = fopen($counter_name, "w");
      fwrite($f,"0");
      fclose($f);
    }
    // Read the current value of our counter file
    $f = fopen($counter_name,"r");
    $counterVal = fread($f, filesize($counter_name));
    fclose($f);
    // Has visitor been counted in this session?
    // If not, increase counter value by one
    if(!isset($_SESSION['hasVisited'])){
      $_SESSION['hasVisited']="yes";
      $counterVal++;
      $f = fopen($counter_name, "w");
      fwrite($f, $counterVal);
      fclose($f); 
    }
    echo  nl2br ("You are visitor number ".$counterVal. " to this site n Today's date is ". date("d/m/Y"));


    $con=mysqli_connect("localhost:8889","root","root","booksmart_properties");
    // Check connection
    if (mysqli_connect_errno())
      {
      echo "Failed to connect to MySQL: " . mysqli_connect_error();
      }
    else{
        echo "we connected";
    }
    // Perform queries 
$result=mysqli_query("SELECT * FROM ListedProperties"); ?> </p>

    <table border="2" style= "background-color: #84ed86; color: #761a9b; margin: 0 auto;" >
  <thead>
    <tr>
      <th>PropertyType</th>
      <th>Description</th>
      <th>RentPrice</th>
        <th>Location</th>
    </tr>
  </thead>
  <tbody>
    <?php
      while( $row = mysqli_fetch_assoc( $result ) ){
        echo
        "<tr>
          <td>{$row['PropertyType']}</td>
          <td>{$row['Description']}</td>
          <td>{$row['RentPrice']}</td>
          <td>{$row['Location']}</td>
        </tr>n";
      }
    ?>
  </tbody>
</table>
 <?php mysql_close($connector); ?>

    //$result=mysqli_fetch_assoc($sql);
    //foreach($result as $key => $val) {
    //print $val; 
    //}
    //echo $result['*'];

    //mysqli_close($con);
//?>

我知道这可能是微不足道的，但我是php的新手，我会感谢所有的帮助，我可以得到

有一个简单的解决方案:

while ( $row = mysqli_fetch_assoc( $result ) ){?>
    <tr>
      <td><?=$row['PropertyType']?></td>
      <td><?=$row['Description']?></td>
      <td><?=$row['RentPrice']?></td>
      <td><?=$row['Location']?></td>
    </tr>
<?php
}

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