Math.min / max.将设定值应用为新范围的百分比

Question

我有一个值数组列表

var v=[0.009865,0.009866,0.009309,0.009831,0.009919,0.009965,0.009806,0.009509,0.009731,0.009888];

我计算最小值，最大值和两者之间的差值，使范围

var max=Math.max.apply(this,v)/100;
var min=Math.min.apply(this,v)/100;
var dif=max-min;
console.dir({'max':max,'min':min,'dif':dif});

控制台。dir显示

max: 0.00009965
min: 0.00009308999999999999
dif: 0.000006560000000000005

然后循环遍历每个值，试图将它们转换为

范围内的百分比

(通过找出当前值比最小值大多少，将答案除以差f并将结果乘以100得到百分比)

for (var i=0;i<v.length;i++){
    v[i]=((v[i]-min)/dif)*100;
    console.log(v[i]);
    }

console.log显示了我真的不期望看到的值(期望在0-100之间)

148962.04268292672
148977.28658536574
140486.43292682915
148443.74999999985
149785.21341463405
150486.43292682915
148062.65243902427
143535.21341463405
146919.35975609746
149312.65243902427

我做错了什么?

我对数学的参考:https://math.stackexchange.com/questions/51509/how-to-calculate-percentage-of-value-inside-arbitrary-range

Answer 1

设置max和min时不要除以100:

var max=Math.max.apply(this,v);
var min=Math.min.apply(this,v);

输出:

84.7560975609757
84.90853658536585
0
79.57317073170726
92.9878048780489
100
75.76219512195132
30.487804878048845
64.32926829268297
88.26219512195112 

Answer 2

您可以使用Array.map来执行此操作，例如:

var v= [0.009865,0.009866,0.009309,0.009831,0.009919,0.009965,
        0.009806,0.009509,0.009731,0.009888]
   ,vv= v.map( function (a) { 
                return ( ( Math.abs(a-this.min) / this.diff() )*100 )
                        .toFixed(2); 
               },
               {min: Math.min.apply(null, v), 
                max: Math.max.apply(null, v),
                diff: function () { return this.max-this.min; } }
              );
 // => returns vv
 // ["84.76", "84.91", "0.00", "79.57", "92.99", "100.00", 
 //  "75.76", "30.49", "64.33", "88.26"]

MDN文档在Array.prototype.map