PHP将查询结果分组为嵌套关联数组

Question

我试图在PHP组查询结果作为一个有效的方式关联数组。我可以使用多个嵌套的foreach循环，检查当前id字段是否与每个数组组的前一个匹配，但我猜有更好/更有效的解决方案来解决这个问题。有人有聪明的解决办法吗?理想的通用函数或方法，可以组任何查询结果集给定的关键字段或嵌套的关键字段数组?

下面是查询结果数组:

Array
(
    [0] => Array
        (
            [look_id] => 3
            [look_name] => Test Look
            [look_description] => description here
            [clothing_article_id] => 1
            [clothing_article_name] => Coat
            [look_clothing_article_attribute_id] => 1
            [look_clothing_article_attribute_name] => Purple
            [clothing_brand_name] => Gap
            [clothing_article_brand_price] => 40.00
            [clothing_article_brand_attribute_price] => 50.00
            [clothing_article_brand_attribute_name] => Purple
        )
    [1] => Array
        (
            [look_id] => 3
            [look_name] => Test Look
            [look_description] => description here
            [clothing_article_id] => 1
            [clothing_article_name] => Coat
            [look_clothing_article_attribute_id] => 2
            [look_clothing_article_attribute_name] => Black
            [clothing_brand_name] => Gap
            [clothing_article_brand_price] => 40.00
            [clothing_article_brand_attribute_price] => 
            [clothing_article_brand_attribute_name] => 
        )
    [2] => Array
        (
            [look_id] => 3
            [look_name] => Test Look
            [look_description] => description here
            [clothing_article_id] => 2
            [clothing_article_name] => Pants
            [look_clothing_article_attribute_id] => 3
            [look_clothing_article_attribute_name] => Cuffed
            [clothing_brand_name] => 
            [clothing_article_brand_price] => 
            [clothing_article_brand_attribute_price] => 
            [clothing_article_brand_attribute_name] => 
        )
)

这就是我要转换成的数组:

Array
(
    'looks' => Array(
        [0] => Array(
            'id' => 3,
            'name' => 'Test Look',
            'description' => 'description here',
            'clothingArticles' => Array(
                [0] => Array(
                    'id' => 1,
                    'name' => 'Coat',
                    'attributes' => Array(
                        [0] => Array(
                            'id' => 1,
                            'name' => 'Purple'
                            'brands' => Array(
                                [0] => Array(
                                    'name' => 'Gap',
                                    'price' => 50.00
                                )
                            )
                        ),
                        [1] => Array(
                            'id' => 2,
                            'name' => 'Black'
                        )
                    ),
                    'brands' => Array(
                        [0] => Array(
                            'name' => 'Gap',
                            'price' => 40.00
                        )
                    )
                ),
                [1] => Array(
                    'id' => 2,
                    'name' => 'Pants',
                    'attributes' => Array(
                        [0] => Array(
                            'id' => 3,
                            'name' => 'Cuffed'
                            'brands' => Array()
                        )
                    ),
                    'brands' => Array()
                )
            )
        )
    )
)

分组关系解释:

一个look可以有1个或多个服装物品。一件服装可以有一个或多个服装品牌。一篇服装文章可以有一个或多个属性。一个服装品牌可以有1个或多个属性。

Answer 1

这不应该太可怕;而不是对内部数组使用数字索引，您应该使用任何唯一标识符，以便您可以对其进行分组。这并不妨碍您在数组本身中使用该标识符。

//seems a little pointless?
$looks = array('looks' => array());
$looks = &$looks['looks'];
while ($row = $result->fetch()) {
    if (!isset($looks[$row->look_id])) {
        $looks[$row->look_id] = array(
            'id' => $row->look_id,
            'name' => $row->look_name,
            'description' => $row->look_description,
            'clothingArticles' => array()
        );
    }
    $look = &$looks[$row->look_id];
    if (!isset($look[$row->clothing_article_id])) {
        //continue this process as needed

Answer 2

执行尽可能多的查询，每个表一个，所有查询都在相同的列上排序，并将行编织在一起:

$q1 = "SELECT * FROM look ORDER BY look_id";
$q2 = "SELECT look_id, article.* FROM look INNER JOIN article USING(look_id) ORDER BY look_id, article_id";
$q3 = "SELECT look_id, article_id, attribute.* FROM look INNER JOIN article USING(look_id) INNER JOIN attribute USING(article_id) ORDER BY look_id, article_id, attribute_id";
// loop on looks
// inner loop on article and add to look
// inner loop on attribute and add to article

或者你可以使用现成的ORM库，比如doctrine